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3 years ago

Help.me................

Mathematics

2 answers:

Svet_ta [14]3 years ago

7 0

Answer:

39º

Step-by-step explanation:

Once the angle 132º and angle ∠BER are supplementary angles (add up to 180 degrees), ∠BER = 48º.

Also, once the sum of a triangle's interior angles is 180º:

∠BER + 93º + (9x+3)º = 180º

48º + 93º + 9x + 3º = 180º

144º + 9x = 180º

9x = 36º

x = 4º

Therefore, the angle ∠EBR (green) is equal to 39º

matrenka [14]3 years ago

3 0

Answer:

the angle itself is 39

Step-by-step explanation:

first the angle 132 is apart of line segment jer so 180-132=48

48+93=141

180-141=39

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Surface Area of a sphere, A grapefruit with C = 14cm.

9966 [12]

Surface area SA: $4\pi r^2$
Circumference C: $2\pi r$ dividing this you get $7=\pi r$ and $r= \frac{7}{\pi}$

Now let's input the radius $r$ into the Surface area formula...
$4\pi r^2\rightarrow 4\pi(\frac{7}{\pi})^2=4\pi(\frac{49}{\pi^2})=\frac{196}{\pi}$

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3 years ago

What is the length of segment TR with T(-4,5) and R(2, -1)

Brilliant_brown [7]

Answer:

The length of segment TR with T(-4,5) and R(2, -1) is 8.49

Step-by-step explanation:

We need to find the length of segment TR with T(-4,5) and R(2, -1)

The length of segment can be found using distance formula.

The distance formula is: $Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Putting values and finding length

We have: $x_1=-4, y_1=5, x_2=2, y_2=-1$

$Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance = \sqrt{(2-(-4))^2+(-1-5)^2}\\Distance = \sqrt{(2+4)^2+(-1-5)^2}\\Distance = \sqrt{(6)^2+(-6)^2}\\Distance = \sqrt{36+36}\\Distance = \sqrt{72}\\Distance=8.49$

We found Distance = 8.49

So, The length of segment TR with T(-4,5) and R(2, -1) is 8.49.

5 0

3 years ago

2. A guy wire for a tree is 20 ft. long, making a 21o angle with the ground. How far is the base of the tree from a stake anchor

Alenkasestr [34]

Answer:

the base of the tree from a stake anchoring the wire is 18.7 ft long

Step-by-step explanation:

A guy wire for a tree is 20 ft. long, making a 21 degree angle with the ground.

It forms a right angle triangle. the hypotenuse of the triangle is 20 ft

The adjacent side of the given angle 21 degree is the base of the tree from a stake

Let x be the base length

$cos(theta)=\frac{adjacent}{hypotenuse}$

$cos(21)=\frac{x}{20}$

$20cos(21)=x$

$x=18.7$

the base of the tree from a stake anchoring the wire is 18.7 ft long

3 0

4 years ago

If u = 6 feet, v = 7 feet, w = 4 feet, x = 7 feet, y = 13 feet, and z = 4 feet, what is the area of the object?

Anastaziya [24]

It depends what type of shape it is if it were a rectangle it would be l x w x h but what a see is a 6 sided figure so it should be a hexagon but a hexagon has all equal sides so it would depend what type of shape it is

6 0

3 years ago

Can someone check this for me? Thanks.

marta [7]

Yes it's SAS
AD = CD (given)
BD = BD (common side )
but since it didn't say AC丄BD
it's no way to prove the angels r 90° :/

but as it already given AD= CD
so it's proven that it's an isosceles triangle
therefore
∠BAD = ∠BCD (base ∠s isos. ∆)

therefore it's SAS (side angel side)

8 0

3 years ago