Answer:
(0,3) One solution
Step-by-step explanation:
Step: Solve x+5y=15for x:
x+5y=15
x+5y+−5y=15+−5y(Add -5y to both sides)
x=−5y+15
Step: Substitute −5y+15for x in 7x+2y=6:
7x+2y=6
7(−5y+15)+2y=6
−33y+105=6(Simplify both sides of the equation)
−33y+105+−105=6+−105(Add -105 to both sides)
−33y=−99
−33y
−33
=
−99
−33
(Divide both sides by -33)
y=3
Step: Substitute 3 for y in x=−5y+15:
x=−5y+15
x=(−5)(3)+15
x=0(Simplify both sides of the equation)
Therefore (0,3) which is one solution
Answer:
8 hours.
Step-by-step explanation:
If you have the 20 as the fee, you'd only have 40 dollars left. If you do 40/ 5 you'd get your answer of 8 hours.
Answer:
40 bricks
Step-by-step explanation:
3 1/2×8
=28
56×20
=1,120
1,120÷28
=40 bricks
Answer:
D)
Step-by-step explanation:
we know that,
Parallel lines have the same slope
given equation is in the form given by
where m is know
as 
, the answer is -⅔
Answer:
Point Critical point
Q (2,0) local minimum
R (-2,1) Saddle
S (2,-1) local maximum
T ( -2,-1) Saddle
O ( -2,0) Saddle
Step-by-step explanation: INCOMPLETE ANSWER INFORMATION ABOUT THE POINTS ARE RARE
f(x,y) = x³ +y⁴ - 6x -2y² +3
df/dx = f´(x) = 3x² -6x
df/dxdx = f´´(xx) = 6x
df/dy = f´(y) = -4y
df/dydy = 4
df/dydx = df/dxdy = 0
df/dydy = f´´(yy)
D = [ df/dxdx *df/dydy] - [df/dydx]²
D = (6x)*4 - 0
D = 6*2*4 D > 0 and the second derivative on x is 6*2 = 12
so D > 0 and df/dxdx >0 there is a local minimum in P
Q(2,1)
D = (6*2)*4 D>0 and second derivative on x is 6*2
The same condition there is a minimum in Q
R ( -2,1)
D = 6*(-2)*4 = -48 D< 0 there is a saddle point in R
S (2,-1)
D = 6*2*4 = 48 D > 0 and df/dxdx = 6*-1 = -6
There is a maximum in S
T ( -2,-1)
D = 6*(-2)*(4) = -48 D<0 there is a saddle point in T
O ( -2,0)
D = 6*(-2)*4 = -48 D<0 there is a saddle point in O
