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1 year ago

What is the inequality of 0 < a < 6 on a numberline

Mathematics

1 answer:

pickupchik [31]1 year ago

7 0

The given inequality is expressed as

0 < a < 6

This means that the values of a that would satisfy the inequality are numbers between 0 and 6 but both 0 and 6 are not inclusive. This would be shown by not making solid circles at 0 and 6. The number line is shown below

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500 increased by 30%

fgiga [73]

500 + 30% equals 650. 30% of 500 equals 150.

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3 years ago

Find the maximum power of 5 which can divide 49!

JulijaS [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

(\tan ^(2)\theta \cos ^(2)\theta -1)/(1+\cos (2\theta ))=

Vitek1552 [10]

(tan²(θ) cos²(θ) - 1) / (1 + cos(2θ))

Recall that

tan(θ) = sin(θ) / cos(θ)

so cos²(θ) cancels with the cos²(θ) in the tan²(θ) term:

(sin²(θ) - 1) / (1 + cos(2θ))

Recall the double angle identity for cosine,

cos(2θ) = 2 cos²(θ) - 1

so the 1 in the denominator also vanishes:

(sin²(θ) - 1) / (2 cos²(θ))

Recall the Pythagorean identity,

cos²(θ) + sin²(θ) = 1

which means

sin²(θ) - 1 = -cos²(θ):

-cos²(θ) / (2 cos²(θ))

Cancel the cos²(θ) terms to end up with

(tan²(θ) cos²(θ) - 1) / (1 + cos(2θ)) = -1/2

7 0

2 years ago

The hourly wages of a sample of 130 system analysts are given below.

atroni [7]

Answer: b. 30%

Step-by-step explanation:

A measure of relative variability is known as coefficient of variation. It is the ratio of the standard deviation to the mean.

i.e. $CV=\dfrac{\sigma}{\mu}$

Given: mean = $\mu=90$

Variance = $\sigma^2 = 729$

$\sigma=\sqrt{729}=27$

Now, $CV=\dfrac{27}{90}=0.3$

in percent , $CV= 0.3\times100\%= 30\%$

Hence, correct option is b. 30%.

8 0

3 years ago

A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0

3 years ago