Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
23.21 is the answer i believe
Step-by-step explanation:
I think the answer is:
A. y=-3+2x
D. y=5x-4
Hope it helps
Answer:
m = 40
Step-by-step explanation:
The triangle inside the circle has 2 equal sides ( the radii ) of the circle, thus
The base angles are congruent both 50°
The 3 angles on the tangent sum to 180°, so
m + 50 + 90 = 180
m + 140 = 180 ( subtract 140 from both sides )
m = 40
Take a pencil put it on the paper then make sure the ink is on the paper then write
