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katrin2010 [14]

3 years ago

5

Question 5 of 5

2 answers:

bogdanovich [222]3 years ago

3 0

Answer:

It's D. 5

Step-by-step explanation:

A^2 + B^2 = C^2

Elis [28]3 years ago

3 0

Answer:

5

Step-by-step explanation:

a.p.e.x

You might be interested in

5 more than the product of 17 and a number is 107. What is the number?

ikadub [295]

Answer:

6

Step-by-step explanation:

subtract 5 from 107 is 102

102 divided by 17 is 6

8 0

3 years ago

A rectangular parcel of land has an area of 3,000 ft2. A diagonal between opposite corners is measured to be 10 ft longer than o

Kazeer [188]

Answer:

40 ft × 75 ft

Step-by-step explanation:

Let x be the one side ( in feet ) of the rectangular parcel,

So, the diagonal between opposite corners = ( x + 10 ) feet,

Let y be the other side of the rectangle ( adjacent to side x ),

The area of the rectangle,

A = x × y,

According to the question,

A = 3000 square ft,

$\implies xy = 3000\implies y=\frac{3000}{x}$

∵ In a rectangle,

$D^2=a^2+b^2$

Where, a and b are the adjacent side of the rectangle and D is the diagonal,

$(x+10)^2 = x^2 + y^2$

$(x+10)^2 = x^2 + \frac{9000000}{x^2}$

$x^2(x+10)^2 = x^4 + 9000000$

$x^2(x^2+100+20x) = x^4 + 9000000$

$x^4+100x^2 + 20x^3 = x^4 + 9000000$

$20x^3 + 100x^2 - 9000000=0$

$x^3 + 5x^2 - 450000 = 0$

By graphing the equation,

We found that,

The only real zeros of the equation is at x = 75,

Hence, the one side of the rectangle = 75 ft,

And, second side = $\frac{3000}{75}$ = 40 ft

Hence, the dimension of the land is 40 ft × 75 ft

3 0

3 years ago

Read 2 more answers

A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its

VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate ( $\dot V$ ), measured in liters per hour, is directly proportional to draining time ( $t$ ), measured in hours. That is:

$\dot V \propto \frac{1}{t}$

$\dot V = \frac{k}{t}$ (Eq. 1)

Where $k$ is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

$\dot V_{s}+\dot V_{l} = \frac{k}{2}$ (Eq. 2)

$\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}$

(ii) <em>Only the small drain is opened</em>

$\dot V_{s} = \frac{k}{t_{l}+3}$ (Eq. 3)

$\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}$

(iii) <em>Only the big drain is opened</em>

$\dot V_{l} = \frac{k}{t_{l}}$ (Eq. 4)

$\frac{\dot V_{l}}{k} = \frac{1}{t_{l}}$

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

$\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}$

$\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}$

$2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}$

$t_{l}^{2}-t_{l}-3 = 0$ (Eq. 5)

Whose roots are determined by the Quadratic Formula:

$t_{l,1}\approx 2.303\,h$ and $t_{l,2} \approx -1.302\,h$

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

$t_{s} = 2.303\,h+3\,h$

$t_{s} = 5.303\,h$

The draining time when only the small drain is opened is 5.303 hours.

7 0

3 years ago

If 10^x = 5, then what is x?

REY [17]

Answer:

what is ∧

Step-by-step explanation:

8 0

3 years ago

What does the value of x have to be so that

Natali5045456 [20]

The value of x is 5

<em><u>Solution: </u></em>

<em><u> The slope of a line is given by formula: </u></em>

$Slope = \frac{ y_2-y_1}{x_2-x_1}$

From given,

$slope = \frac{11}4}\\\\(x_1, y_1) = (x, -7)\\\\(x_2, y_2) = (-1, 4)$

<em><u>Substituting the values we ge</u></em><em><u>t,</u></em>

$\frac{11}{4} = \frac{4+7}{-1-x}\\\\-11 - 11x = 11 \times 4\\\\-11-11x = 44\\\\11x = -11-44\\\\11x = 55\\\\x = 5$

Thus the value of x is 5

5 0

3 years ago