Use this picture to answer the questions below.

Which best describes the range of the function f(x) = 2/3(6)x after it has been reflected over the x-axis?

liq [111]

Your post (" f(x) = 2/3(6)x ") would be clearer and less ambiguous if you'd please format it as follows:

f(x) = (2/3)(6)^x. The (2/3) shows that 2/3 is the coefficient of the exponential function 6^x. Please use " ^ " to indicate exponentiation.

Start by graphing f(x) = (2/3)(6)^x. The y-intercept, obtained by setting x=0, is (0, 2/3). Can you show that the value of f(x) is (2/3)*6, or 4, at x=1, (2/3)*6^2, or 24, at x = 2, and so on? What happens if x becomes increasingly smaller? The graph approaches, but does not touch, the x-axis.

If you complete this graphing assignment, then all you'd have to do is to flip the whole graph over vertically, reflecting it in the x-axis. You'll see that the graph never touchs the x-axis. Therefore, the range of this flipped graph is (-infinity, 0).

7 0

3 years ago

Read 2 more answers

Jill made the model below to show the quotient 1.28 divided 4 pls someone help

quester [9]

Answer:

C

Step-by-step explanation:

6 0

3 years ago

Can someone please help me with this question

Anton [14]

It seems the first line has to be

1. AB=CD and AD=CB 1. given

2. AC=AC 2. Reflexivity (things are equal to themselves)

3 $\triangle$ ACB $\cong$ $\triangle$ CAD 3. SSS

4. $\angle$ 1 = $\angle$ 4. Corresponding parts of congruent triangles

5 DC || AB 5. Congruent alternate traversal angles imply parallel lines

5 0

3 years ago

the change in water vapor in a cloud is modeled by a polynomial function, c (x). describe how to find the x - intercepts of c (x

lukranit [14]

The change in the water vapors is modeled by the polynomial function c(x). In order to find the x-intercepts of a polynomial we set it equal to zero and solve for the values of x. The resulting values of x are the x-intercepts of the polynomial.

Once we have the x-intercepts we know the points where the graph crosses the x-axes. From the degree of the polynomial we can visualize the end behavior of the graph and using the values of maxima and minima a rough sketch can be plotted.

Let the polynomial function be c(x) = x ² -7x + 10

To find the x-intercepts we set the polynomial equal to zero and solve for x as shown below:

x ² -7x + 10 = 0

Factorizing the middle term, we get:

x ² - 2x - 5x + 10 = 0

x(x - 2) - 5(x - 2) =0

(x - 2)(x - 5)=0

x - 2 = 0 ⇒ x=2

x - 5 = 0 ⇒ x=5

Thus the x-intercept of our polynomial are 2 and 5. Since the polynomial is of degree 2 and has positive leading coefficient, its shape will be a parabola opening in upward direction. The graph will have a minimum point but no maximum if the domain is not specified. The minimum points occurs at the midpoint of the two x-intercepts. So the minimum point will occur at x=3.5. Using x=3.5 the value of the minimum point can be found. Using all this data a rough sketch of the polynomial can be constructed. The figure attached below shows the graph of our polynomial.