All categories

2 years ago

X+15° ) + + (x+20°)+(x-10)

Mathematics

1 answer:

il63 [147K]2 years ago

3 0

Answer:

3x+35°-10

Step-by-step explanation:

remove the parentheses so the equation is

x+ 15°+x+20°+(x-10)

You might be interested in

Place the indicated product in the proper location on the grid. [4 - (3c - 1)] [6 - 3c -1)]

mash [69]

[4 - (3c - 1)][6 - (3c - 1)]
[4 - 3c + 1][6 - 3c + 1]
[-3c + 4 + 1][-3c + 6 + 1]
[-3c + 5][-3c + 7]
-3c[-3c + 7] + 5[-3c + 7]
-3c[-3c] - 3c[7] + 5[-3c] + 5[7]
9c² - 21c - 15c + 35
9c² - 36c + 35

7 0

3 years ago

Identify the situation that involves opposite quantities adding up to zero Climbing up 6 feet and climbing down 4 feet Hiking 10

ivolga24 [154]

9514 1404 393

Answer:

(b) Hiking 10 feet due north, then hiking 10 feet due south

Step-by-step explanation:

Any pair of numbers that totals zero will be a pair of opposites. The offered choices are ...

+6 -4 = 2 . . . not zero

+10 -10 = 0

+2 -3 = -1 . . . not zero

+5 -3 = 2 . . . not zero

Hiking 10 feet due north, then hiking 10 feet due south is a situation involving opposite numbers adding up to zero.

3 0

3 years ago

What is the relationship between the 6's in the number 6647

marta [7]

We can break down the number 6647 into:
6647=6000+600+40+7
The first 6 in the number is in the thousands place (6,000), and the second 6 is in the hundreds place (600).
The first 6 is 10 times greater than the second one.

8 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$