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2 years ago

How many cubes with edge lengths of 1/3 inch are needed to build a cube with an edge length of 1 inch?

Mathematics

2 answers:

zavuch27 [327]2 years ago

8 0

27 cubes would be needed for this

Debora [2.8K]2 years ago

3 0

Answer:

27 cubes are needed because you'd need a 3x3x3 cube

(got from someone else)

Step-by-step explanation:

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Liv hizo un ponche al mezclar 2,8 litros de jugo de naranja, 0,75 litros de jugo de piña y 1,2 litros de ginger ale. Liv dividir

Juli2301 [7.4K]

Answer is 24............

5 0

3 years ago

Find the length indicated

Contact [7]

Answer:

the answer is b, 12

Step-by-step explanation:

16-4=12

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%285%20-%20x%29%28x%20-%203%29" id="TexFormula1" title="(5 - x)(x - 3)" alt="(5 - x)(x - 3)" a

professor190 [17]

Answer:

15x

Step-by-step explanation:

because i multiply i side by side and copy the variable

3 0

2 years ago

Read 2 more answers

(N^3 - N^4) - (3n^3- 7n^4)

Free_Kalibri [48]

If you would like to solve (n^3 - n^4) - (3n^3 - 7n^4), you can do this using the following steps:

(n^3 - n^4) - (3n^3 - 7n^4) = <span>n^3 - n^4 - 3n^3 + 7n^4 = n^3 - 3n^3 - n^4 + 7n^4 = -2n^3 + 6n^4
</span>
The correct result would be <span>-2n^3 + 6n^4.</span>

3 0

3 years ago

(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw

slavikrds [6]

Answer:

a. $\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. $C_{0}=122$

c. $k=-0.00259$

d. $t=153.39838\\$ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

$Tm=68$

$\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. The differential equation obtained is a differential equation of separable variables:

$\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122$

c. After 33 minutes of serving the coffee has cooled to 180°:

$T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259$

$150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\$

8 0

3 years ago