Any help? (with photos)

If y = 2x2 – 4x, what is the value of y when x equals 5. A.10 B.30 C.80 D.480

Ainat [17]

Answer:

The value of y in the given equation is B. 30.

Step-by-step explanation:

y = 2x² - 4x x = 5

y = 2(5)² - 4(5) Plug 5 in for x

y = 2(25) - 20 Square 5 and multiply 4 by 5

y = 50 - 20 Multiply 2 by 25

y = 30

Hope this helps,

❤A.W.E.S.W.A.N.❤

6 0

3 years ago

to communication companies offer calling plans with company X it cost $0.35 to connect and then $0.05 for each minute with compa

Mama L [17]

Answer:

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

Step-by-step explanation:

Given:

Cost of X company = $\$ 0.35+(\$0.05\times 1 \ minute)$

Cost of Y Company = $\$ 0.15+(\$0.04\times 1 \ minute)$

for n minutes

Cost of X company for n minutes = $\$ 0.35+(\$0.05\times n \ minute)$

Cost of Y Company for n minutes = $\$ 0.15+(\$0.04\times n \ minute)$

Difference for n minutes we get by Subtracting Cost of Y Company for n minutes by Cost of X company for n minutes

Difference for n minutes = $(\$ 0.2+\$ 0.01n)$ = $(0.2+0.01n)\times 10^2 \ cents$

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

6 0

3 years ago

Can someone help me with these?

jolli1 [7]

I hope this helps you

4 0

3 years ago

The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml

irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63$

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$