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3 years ago

Use the substitution method to solve the system of equations. y = -8x 4x - y = 3 O AG-2 O B. (6-1 oc c. (6.-4 D. G-4

Mathematics

2 answers:

PtichkaEL [24]3 years ago

8 0

Answer:

x = 1/4

y = -2

Step-by-step explanation:

Triss [41]3 years ago

6 0

<h2>Known : </h2>

y = -8x

4x - y = 3

<h2>Asked: </h2>

Use the substitution method to solve the system of equations ?

<h2>Answered:</h2>

<h3>Substitution y</h3>

4x - y = 3

4x - (-8x) = 3

4x + 8x = 3

12x = 3

x = 3/12

x = 1/4

<h3>Substitution x</h3>

4x - y = 3

4(1/4) - y = 3

4/4 - y = 3

1 - y = 3

-y = 3 - 1

-y = 2

y = -2

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3 years ago

Read 2 more answers

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4 years ago

Which expression is the completely factored form of x^6– 64y^3?

PSYCHO15rus [73]

Answer:

$(x^2-4y)(x^4+4x^2y+16y^2)$

Step-by-step explanation:

<u>Factoring</u>

We need to recall the following polynomial identity:

$(a^3-b^3)(a-b)(a^2+ab+b^2)$

The given expression is:

$x^6- 64y^3$

To factor the above expression, we need to find a and b, knowing a^3 and b^3. a is the cubic root of a^3, and b is the cubic root of b^3:

$a=\sqrt[3]{x^6}=x^2$

$b=\sqrt[3]{64y^3}=4y$

Now we apply the identity:

$x^6– 64y^3=(x^2-4y)[(x^2)^2+(x^2)*(4y)+(4y)^2]$

Operating:

$x^6– 64y^3=(x^2-4y)[x^4+4x^2y+16y^2]$

The remaining factors cannot be factored in anymore. Thus the completely factored form is:

$\boxed{(x^2-4y)(x^4+4x^2y+16y^2)}$

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3 years ago

Can anyone help please!!!

masha68 [24]

Answer:

There is an answer for this asked by someone else

Step-by-step explanation:

4 0

3 years ago

Use the substitution method to solve the system of equations. y = -8x 4x - y = 3 O AG-2 O B. (6-1 oc c. (6.-4 D. G-4​

Use the substitution method to solve the system of equations. y = -8x 4x - y = 3 O AG-2 O B. (6-1 oc c. (6.-4 D. G-4