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Whitepunk [10]
3 years ago
14

Standard form of 5000000+400000+400+30+7?​

Mathematics
1 answer:
ipn [44]3 years ago
6 0

Answer:

Step-by-step explanation:

5400437

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What is the median of this set of data?
Vladimir [108]

Answer:

The median would be 103.

8 0
3 years ago
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At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]
denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

f(x) = x^3-2x^2-4x+1 in the interval  [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

f(1) = 1-2-4+1 = -4\\f(0) = 1

The value

\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5

Find derivative for f

f'(x) = 3x^2-4x-4

Equate this to -5 to check mean value theorem

3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1

We find that 1/3 lies inside the interval (0,1)

4 0
3 years ago
Chang runs each lap in 5 minutes. He will run at the most 30 minutes today. What are the possible numbers of laps he will run to
Ipatiy [6.2K]

Answer:

6

Step-by-step explanation:

all you have to do is 30 / 5 what equals 6

4 0
3 years ago
Trọng lượng một sp là bnn pp chuẩn với trung bình là 20,5 và độ lệch chuẩn là 2. Lấy ngẫu nhiên 4 sp để kiểm tra thì với xs 0,95
Illusion [34]
You need to make this is all languages if you want help thank you . :)
8 0
3 years ago
In the year 2005 , a total of 750 fish were introduced into a manmade lake . The fish population was expected to grow at a rate
xxTIMURxx [149]

Answer:

The fish population will be in 2050 = 27,123

Step-by-step explanation:

Given,

In 2005, the total number of fish were introduced (fish population), PV = 750

The growth rate, i = 8.3% = 0.083

The difference between 2050 and 2005 is (2050 - 2005), n = 45 years

We need to solve this problem with the help of future value of compounding. We know, FV = PV (1+i)^n, where, PV = present value, i = interest rate, n = period.

Therefore, the fish population will be in 2050 = 750 x (1 + 0.083)^45

The fish population will be in 2050 = 27,123.26

2050 fish population = 27,123 (Nearest to whole number).

3 0
3 years ago
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