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dsp73
2 years ago
5

5) Choose which postulate proves the triangles congruent.

Mathematics
1 answer:
LuckyWell [14K]2 years ago
5 0

Answer:

AAS

Step-by-step explanation:

HEHE

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The sum of three whole numbers in 27. The mean of the three whole numbers is 9, and the greatest number is twice the least numbe
Kitty [74]
B I think. Good luck
6 0
3 years ago
Read 2 more answers
17. Santino loves to rock different colored polo shirts every day. He recently wore the following colors:
qaws [65]

Answer:

The mode for the colors that Santino wore recently is Blue.

Step-by-step explanation:

The mode of a data set is the term or observation that presents most of the time.

The frequency table of different colored polo shirts worn by Santino is:

Color      Frequency

Yellow            2

 Blue              3

Green             1

 Pink              1

Brown            1

Orange          1

Chartreuse    1

Black              1

Puce              1

The color Blue has the highest frequency, i.e. 3.

So, the mode for the colors that Santino wore recently is Blue.

3 0
2 years ago
Can you guys help me with this question?
IRINA_888 [86]
So below m in the chart, is shows what m equals for you to substitute in the equation

So the second blank would be 42.
Since 7*6=42.

The third blank would equal to 56.
Since 7*8=56
5 0
3 years ago
{y=-x+1<br> {y=4x-14<br> please help me <br> my paper is due today
Temka [501]

- x + 1 = 4x - 14 \\  - x - 4x =  - 14 - 1 \\  - 5x =  - 15 \\ x = 3

Substitute x = 3 in any given equations. I will do in y = - x + 1

y =  - x + 1 \\ y =  - 3 + 1 \\ y =  - 2

Therefore the answer is (3,-2)

7 0
2 years ago
A factory produce bicycles at a rate of 110+0.5t^2-0.9t bicycles per week (t in weeks)
klasskru [66]

Answer:

221

Step-by-step explanation:

Day 8 is the first day of the second week.

Day 21 is the last day of week 3.

We need to know the n umber of bicycles made from t = 1 to t = 3

The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.

We need to integrate the function with the limits of 1 to 3.

\int_{1}^{3} (110 + 0.5t^2 - 0.9t) dt

\int_{1}^{3} (110 + \dfrac{t^2}{2} - \dfrac{9t}{10}) dt

= 110t + \dfrac{t^3}{6} - \dfrac{9t^2}{20} \Biggr|_{1}^{3}

= 330.45 - 109.72

= 220.7333

Answer: 221

3 0
3 years ago
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