Answer:
Offset bits: 3-bits
Set number of cache: 12-bits
Tag bits: 7-bits
22-bit physical address
Explanation:
Since the system is 32K so,
=2⁵.2¹⁰
=2¹⁵
As we know that it is 8-way set associative so,
=2¹⁵/2³
=2¹⁵⁻³
=2¹²
2¹² are cache blocks
22-bit physical address
Off-set bits are 3 as they are calulated from 8-way set associative information.
Set number of cache : 12-bits
For tag-bits:
Add off-set bits and cache bits and subtract from the total bits of physical address.
=22 - (12+3)
=22 - 15
=7
e. uhmmm
19+21=30
like....
easy.
What grade class is this? I wanna do it cause it easy AFef
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we will contact moderators to find your question and remove it, and hopefully, they will refund the points, which is not up to me.
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The test that a computer needs to pass after a human's conversation with it and not be able to tell if it was a machine or a human is; Turing Test
<h3>Test of Computers</h3>
The correct answer to the blank portion of the question is Turing test. This is because Turing Test is a test of a computer's ability to exhibit intelligent behavior that is equivalent to, or indistinguishable from, that of a human's behavior.
Finally, If the evaluator cannot reliably tell the computer from the human, the machine is said to have passed the test.
Read more about Test of Computer at; brainly.com/question/21283135
