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const2013 [10]
3 years ago
15

Use a colon before a list and put one space after a colon. True False

Computers and Technology
2 answers:
german3 years ago
8 0
Good ............sure true ;)
IceJOKER [234]3 years ago
5 0
True

<span>Colons are used to introduce an item or a list of two or more items. One key thing to remember is that you should always use colons in statements that are complete and never in sentence fragments. In most English style guides that address this matter, only one space is recommended after a colon and no space should be placed before.</span>


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Write a program that creates a linked list object of 10 characters and creates a second list object containing a copy of the fir
slamgirl [31]

Answer:

Below code is in c++ with explanation.

Explanation:

Explanation is in comment format, any line starting with //.

#include <iostream>

#include <cstdlib>

using namespace std;

//creating a Node struct which holds node data

struct Node {  

  char data;  

  struct Node *next;  

};  

//creating variable of Node as head

// this head is the start point of ordered Linked list

struct Node* head = NULL;    

// This method is used to insert new value in node

void insert(char new_data) {  

// allocating the memory for new node

  struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));  

// assigning the data to new node

  new_node->data = new_data;  

// If head == null then it means we are inserting first value

// it will return after creating first node and assign it to

// head as head is the entry point

  if(head == NULL){

    new_node->next=NULL;

   head=new_node;

    return;

  }

// Now we need to treverse to end of linked list

// that's why creating a lastNode variable  

// As we don't want our head to point any other node

// except first node

  Node* lastNode = head;

  while(lastNode->next != NULL){

   lastNode=lastNode->next;

  }

// as last node next will be null to end the traversing  

// on linked list

  new_node->next= NULL;

// assigning last node to its previous node  

  lastNode->next = new_node;  

   

}  

// This variable will hold the first node for reverse linklist

struct Node* reverseHead = NULL;    

// This method will reverse the ordered linklist

void reversLinkList(){

  Node* lastNode = head;

// traversing the ordered linklist

  while(lastNode!= NULL){

// creating new linked list

   struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));  

   new_node->data = lastNode->data;  

   new_node->next = reverseHead;  

   reverseHead = new_node;  

   lastNode = lastNode->next;

  }

   

}

// display method will travers the linklist that

// was passed throw paramter

void display(Node* node) {  

  struct Node* ptr;

  ptr = node;

  while (ptr != NULL) {  

     cout<< ptr->data <<" ";  

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  }  

}  

// main method is the entry point of this program

int main() {  

// adding 10 nodes by calling insert method

  insert('a');

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  insert('d');

  insert('e');

  insert('f');

  insert('g');

  insert('h');

  insert('i');

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  cout<<"The Ordered linked list is: ";

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  display(head);  

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  reversLinkList();

// calling display method with reverseHead to display  

// reversed linklist

  display(reverseHead);

   

  return 0;  

}

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