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3 years ago

Kelly can walk 8 1/3 kilometers in one hours. How far can she walk in 2 2/5 hours?

Mathematics

1 answer:

gulaghasi [49]3 years ago

6 0

Answer:

20 km

Step-by-step explanation:

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Use the Distributive Property to expand<br> the expression:<br> 2 (y + 5x - 3)

ankoles [38]

2y+10x-6, just distribute the 2!

8 0

3 years ago

If stratified random sampling with proportional allocation is used to select a sample of 25 high schools, how many would be sel

gregori [183]

Answer:

02 High Schools would be selected from the stratum with a percent-free-lunch value of 40 less than or equals x.

Step-by-step explanation:

As the sample size needed is 25 and total schools are 100 so this indicate 1 school in each 4 schools is to be selected. This is given as

$n=\frac{n_{total}}{n_{sample}}\\n=\frac{100}{25}\\n=4$

Now as the schools with percent free lunch are 8 so now

$n=\frac{n_{total}}{n_{sample}}\\n=\frac{8}{2}\\n=2$

So only 2 schools will be selected in this regard.

7 0

3 years ago

18. Use Pascal's triangle to find the coefficients of the expanded polynomial (a + b)^3.

Over [174]

Answer:

Step-by-step explanation:

Hello, let's compute the first lines of the Pascal's triangle.

1 1

1 2 1

1 3 3 1

So for this question,

$(a+b)^3=a^3+3a^2b+3ab^2+b^3$

And then, the correct answer is A.

Thank you

6 0

4 years ago

Trying to determine function of g(x).

mario62 [17]

Answer:

To find f(g(x)), we just substitute x = g(x) in the function f(x). For example, when f(x) = x2 and g(x) = 3x - 5, then f(g(x)) = f(3x - 5) = (3x - 5)2.

3 0

2 years ago

Read 2 more answers

Given f '(x) = (2 - x)(6 - x), determine the intervals on which f(x) is increasing or decreasing. (2 points)

weeeeeb [17]

Answer:

Decreasing (2, 6); increasing on (-∞, 2) U (6, ∞)

Step-by-step explanation:

To determine where $f(x)$ is increasing or decreasing, we set $f'(x)=0$ and check for the intervals.

We see that $f'(x)=0$ when either $x=2$ or $x=6$ . Therefore, we'll need to check the intervals $(-\infty,2)$ , $(2,6)$ , and $(6,\infty)$

For the interval $(\infty,2)$ , we can pick $x=0$ . This means that $f'(0)=(2-0)(6-0)=(2)(6)=12>0$ , showing that $f(x)$ increases on the interval $(-\infty,2)$

For the interval $(2,6)$ , we can pick $x=4$ . This means that $f'(4)=(2-4)(6-4)=(-2)(2)=-4$ , showing that $f(x)$ decreases on the interval $(2,6)$

For the interval $(6,\infty)$ , we can pick $x=7$ . This means that $f'(7)=(2-7)(6-7)=(-5)(-1)=5>0$ , showing that $f(x)$ increases on the interval $(6,\infty)$

Therefore, $f(x)$ is increasing on $(-\infty,2)\cup(6,\infty)$ and is decreasing on $(2,6)$ .

3 0

3 years ago