We have 60 gallons of 20% antifreeze.
How much 70% antifreeze do we add to get 60% antifreeze?
We'll make "x" the gallons of 70% we must add.
.20 * 60 + .70 x = .60 * (60 + x)
12 + .70x = 36 + .60x
.10x = 24
x = 240 gallons of 70% antifreeze.
Source
1728.com/mixture.htm (see example B)
Answer:
The last one (4 sqare root 3)
Step-by-step explanation:
The square root of 16 is 4 so then it would be 4 sqroot 3
Answer:
When you have iodine gas at 200 degrees, the temperature and thus pressure as so high, that when cooling down you enter the liquid phase. And when some of this gas then condenses, the pressure drops. So the remaining part of the gas can sublime.
Step-by-step explanation:
5280 feet in 1 mile
3600 seconds in an hour
58(5280) / 3600 = 306240/3600 = 85.06 ft per sec or if u need it rounded, it is 85.1
So in a proportion 23.4 over 5.49 equals 1 over o and multiply 5.49•1=23.4o
5.49=23.4o divide by 23.4 on both sides and that equals 4.26 per oz