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3 years ago

Chantay made this square picture. She wants to glue yarn around the border to make a frame. How much yarn does she need?

Mathematics

1 answer:

statuscvo [17]3 years ago

8 0

Answer:

60 I

Step-by-step explanation:

because it would be 15 times 4 right I think

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Write an equation of the line in slope-intercept form. y=

Phantasy [73]

Y= mx+b
Y= 1x -2
Good luck

3 0

3 years ago

Draw to explain how you would make a ten to find 5+8.

erica [24]

Since 2+8 =10 you would just have 3 left to add so it would be 10+3=13

4 0

3 years ago

John has a roll containing 24 2/3 feet of wrapping paper he wants to divide it into 11 pieces first though he must cut off five

Simora [160]

take 23 2/3 and subtract 6 to get 53/3 or 17 2/3 or 17.667

then you take 17.667 and divide by 11 to get 1.606

6 0

3 years ago

45% of what number is 63

ollegr [7]

Answer:

140.

Step-by-step explanation:

7 0

3 years ago

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

4 years ago