1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Agata [3.3K]
3 years ago
13

When analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This adjustm

ent can be done by normalizing to values between 0 and 1, or throwing away outliers.
For this program, adjust the values by dividing all values by the largest value. The input begins with an integer indicating the number of floating-point values that follow.
Output each floating-point value with two digits after the decimal point, which can be achieved as follows:
print('{:.2f}'.format(your_value))
Ex: If the input is:
5 30.0 50.0 10.0 100.0 65.0
the output is:
0.30 0.50 0.10 1.00 0.65
The 5 indicates that there are five floating-point values in the list, namely 30.0, 50.0, 10.0, 100.0, and 65.0. 100.0 is the largest value in the list, so each value is divided by 100.0.
For coding simplicity, follow every output value by a space, including the last one
1 #include
2 #include
3 #include
4 using namespace std;
5
6 int main() {
7
8 /* Type your code here. */
9
10 return 0;
11 }
12
Computers and Technology
1 answer:
Ksivusya [100]3 years ago
7 0

Answer:

5.23 LAB: Adjust values in a list by normalizing When analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This can be done by normalizing to values between 0 and 1, or throwing away outliers.

Explanation:

You might be interested in
Floating point numbers?
blondinia [14]

Answer:

Thank you so much!!!

God bless you!!!

You the best!!!

Explanation:

4 0
3 years ago
What is a memory unit in computer​
Nina [5.8K]
The amount of data that can be stored in the storage unit.
4 0
2 years ago
Grade Average Lab Assignment Purpose: The goal of this lab assignment is to learn how to use for loops and if/else commands. Wri
miss Akunina [59]
<h2>Answer:</h2><h2></h2>

//class to test the Grade class

public class GradeTest{

    public static void main(String []args){        

       //create the grades to be averaged

      double [] grades = {23, 45, 67, 12.6};

       

       //create an object of the Grade class and

       //pass in the necessary arguments to the constructor

       Grade grade = new Grade("John", grades);

       

       //print out the results from the Grade object.

       System.out.println("Your name is " + grade.getName());

       System.out.println("Your average score is " + grade.getAverage());

       System.out.println("Your letter grade is " + grade.getLetterGrade());

       

   }

}  //End of the GradeTest class

//The Grade class

class Grade {

   

   //create instance variables

   private String name;

   private double [] grades;

   

   //constructor for the class

  public Grade(String name, double [] grades){

       

       //initialize the instance variables

      this.name = name;

       this.grades = grades;

       

   }

   

   //method to return the name of the student

  public String getName(){

       //return the name

       return this.name;

   }

   

   

   //method to calculate the average of the grades

  public double getAverage(){

       

       double [] grades = this.grades;

       

       //initialize some needed variables

       double sum = 0;

       double average = 0;

       

       //loop through the grades array and add each element to the sum variable

       for(int i =0; i < grades.length; i++){

           sum += grades[0];    

       }

       

       //calculate the average

      average = sum / grades.length;

       

       //return the average grade

       return average;

     

   }

   

   

   //method the calculate the letter grade from the average

   public char getLetterGrade(){

       

       //initialize some variables

      double average = this.getAverage();

       char letterGrade;

       

       //check the average and determine its corresponding letter grade

       if(average >= 40 && average < 45){

           letterGrade = 'E';

       }

       else if(average >= 45 && average < 50){

           letterGrade = 'D';

       }

       else if(average >= 50 && average < 60){

           letterGrade = 'C';

       }

       else if(average >= 60 && average < 70){

           letterGrade = 'B';

       }

       else if(average >= 70 && average <= 100){

           letterGrade = 'A';

       }

       else {

           letterGrade = 'F';

       }

       //return the letter grade

       return letterGrade;

       

   }

   

}   //End of the Grade class

<h2>Sample Output:</h2>

Your name is John

Your average score is 23.0

Your letter grade is F

<h2>Explanation:</h2>

The code above is written in Java and it contains comments explaining important parts of the code. It also contains a sample output got from running the program. To run this on your machine, copy the code and save in a file named GradeTest.java

3 0
3 years ago
It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

5 0
3 years ago
If you were a developer of software, what kind of software package would you develop? why ?​
Goshia [24]

Answer:

Software that would help my grandparents in the North end much money and help stop post harvest loss due to inadequate weather information Climate change etc

Explanation:

The app willbe able to tellif a soil is suitable forCropsthrough my othertechnologiesthat willcome with app it will alsodetect the whetherpattern accuratelyprovide securityin the farmand help farmers selltheir products online

7 0
3 years ago
Other questions:
  • How do I change my age on here?-<br> Why did it set it to 18???
    5·2 answers
  • Gina is upgrading your computer with a new processor. She installs the processor into your motherboard and adds the cooling syst
    5·2 answers
  • What are the three types of network topologies used today?
    13·1 answer
  • A technician is trouble-shooting an IDE hard drive that is emitting a humming sound. They suspect a faulty connector. Which of t
    6·1 answer
  • HELP PLEASE ASAP!!! Does anyone know how to fix a broken iPhone which when I connect it to the charger it comes up with the Appl
    5·1 answer
  • In the mouse properties window you can
    6·1 answer
  • 9.6 Code Practice, this is in Python, I need its quick!
    13·1 answer
  • 4. In Drag and Drop method of Excel , to copy the data , you need to press __________ key while dragging the cells.
    7·1 answer
  • Can anyone tell me about Microsoft some important features for partical
    11·1 answer
  • 1. The opportunity to create several equations for launching program files is called
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!