Answer:
First: $65
Second: $115
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=180 since their sum is 180.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=180, rearrange to b=180-a and substitute into 15a+5b=1550.
15a + 5 (180-a)=1550
15a+900-5a=1550
10a+900-900=1550-900
10a=650
a=$65 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
65+b=180
65-65+b=180-65
b= $115 was charged by the second mechanic
4(2y-9) is your answer factored completely out
The intercepts are the points where the graph crosses the x or y-axis
- <em>The x-intercepts changed from 0 to </em>
<em>.</em> - <em>The y-intercepts changed from 0 to 3</em>
The functions are given as:


<u>Function f(x)</u>

The x-intercept is calculated as follows:
Set f(x) to 0

Solve for x

The y-intercept is calculated as follows:
Set x to 0


Hence, the intercepts are 0
<u>Function g(x)</u>

The x-intercept is calculated as follows:
Set g(x) to 0

Solve for x


The y-intercept is calculated as follows:
Set x to 0


The x-intercepts are
, while the y-intercept is -3
By comparing the intercepts of f(x) and g(x),
- <em>The x-intercepts changed from 0 to </em>
<em>.</em> - <em>The y-intercepts changed from 0 to 3</em>
Read more about intercepts at:
brainly.com/question/3334417
The answer is B - vertical angles
Answer:
The opposite of 12 is -12.
Step-by-step explanation:
-12, -11, -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
All you have to do is do the negative version of that same original number.