A(r)=3.14r^2, when r=5
A(5)=3.14(5^2)
A(5)=3.14(25)
A(5)=78.5 u^2
Answer:
k = 33
Step-by-step explanation:
7 + k/3 = 18
=>7 + k/3 -7 = 18 - 7
=>k/3 = 11
=>(k/3) * 3 = 11 * 3
=>k = 33
Area is 6000 yd2
LW = 6000
field must be 40 yards longer than its width
L = W + 40
Replace L with W+40 in 1st equation to solve for Width
(W+40)(W) = 6000
W2 + 40W - 6000 = 0
This is a quadratic but is factorable
Factors of -6000 that add to 40 are (100)(-60)
(W+100)(W-60) = 0
W = -100 or W = 60
Since the width will not be negative discard -100
The width is 60 yards
Length is W+40 = 100 yards
Answer:
7/12
Step-by-step explanation:
well first you have subtract 2/3 from 1/12 how you do that is that you have to change the denominator into twelve by multiplying 3 times 4 and 2 times for which you get 8/12 them subtract 8/12 from 1/12 which is 7/12
