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3 years ago

I really need help with this "Simplify this equation."

Mathematics

1 answer:

Tju [1.3M]3 years ago

3 0

Answer:

2nd one

Step-by-step explanation:

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The community center has a pottery class each month. Each student pays $15 for the class and $27 for materials. This month the p

Dominik [7]

If you add $15 + $27 because that's how much it costs for each student, you get $42. Then you divide $714 by $42, you get 17 and that's how many students are in the class this month.

3 0

3 years ago

Read 2 more answers

Solve for y, 3xy+x=9 Then find f(x) when x=2

AnnyKZ [126]

3xy+x=9
3xy = 9 - x
y = 3/x - 1/3

if x = 2
f(2) = 3/2 - 1/3
f(2) = 9/6 - 2/6
f(2) = 7/6
f(2) = 1 1/6

5 0

3 years ago

Translate to words 6.4 - 3x + 8

Sedaia [141]

Six point four minus three x plus eight...

Hope it works... not sure if it asked for that, I’d put that unless explained otherwise

Good luck!

8 0

4 years ago

What are the possible rational roots of the polynomial equation? 0=2x7+3x5−9x2+6

RoseWind [281]

Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

5 0

3 years ago

Who won the race between the two balls of string

motikmotik

The higher one I think

7 0

3 years ago