We can do like we did before, distribute the denominator,
Answer:
(0.7- -5x-0.2)= (0.7-1)= -1.7
-1.7/0.3 = -5.66666666667
Availability of first truck probability P (1) = 0.74
Availability of second truck probability P (2) = 0.57
Availability of both truck probability P (1 and 2) = 0.46
So the probability of at least one available P (1 or 2) = P (1) + P (2) - P (1 and 2) = 0.74 + 0.57 - 0.46 = 0.85
Now the probability of at neither available = 1 - P (1 or 2) = 1 – 0.85 = 0.15
Parallel means same slope, so in the image, line PQ is connected by a line. The other point I made has a line parallel through it.
the 1st one
third one
fourth one
the last one
each of the equation has one of the common factor out
