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JulsSmile [24]
3 years ago
11

Which strategy would not correctly solve this story problem? Jason bought a bagel and a cup of coffee each Saturday. Each bagel

costs $2 and each cup of coffee costs $1. How much money had Jason spent in 8 weeks? A. Make a table. Week 1 2 3 4 5 6 7 8 Total Cost ($) 3 6 9 12 15 18 21 B. Translate into an equation. 8 × (2 + 1) = d C. Use objects to model the problem. Take 8 pieces of play money. Take away 1 piece for the coffee and 2 pieces for the bagel. D. Use logical reasoning. In 1 week Jason spent $2 for a bagel plus $1 for coffee. He spent a total of $3. So to figure out how much Jason spent in 8 weeks, multiply $3 by 8.
Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0
This answer is not correct

<span>C. Use objects to model the problem. Take 8 pieces of play money. Take away 1 piece for the coffee and 2 pieces for the bagel.</span>
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What does the quadratic function f(x)=x^2-10x+9 look like when it is rewritten in the form f(x) = a (x-h) + k
Tatiana [17]

ANSWER

When f(x)=x^2-10x+9 is written in the form f(x)=a(x-h)^2+k, it looks like f(x)=(x-5)^2-16


EXPLANATION

To write  f(x)=x^2-10x+9 in the form f(x)=a(x-h)^2+k, we have to complete the squares.


We add and subtract half the coefficient of x square.


f(x)=x^2-10x+(-5)^2-(-5)^2+9


The first three terms of the function is now a perfect square.

f(x)=(x-5)^2-25+9

We now simplify rto obtain,

\Rightarrow f(x)=(x-5)^2-16





6 0
3 years ago
Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
hram777 [196]

Answer:

(1,1)

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points (x_1,y_1)\,,\,(x_2,y_2) is equal to \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So,

EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

Put (x,y)=(1,1)

\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

This is true.

So, the point (1,1) satisfies the equation \sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

So, point H is (1,1).

7 0
3 years ago
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Mumz [18]

Answer:

times the numbers

Step-by-step explanation:

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3 years ago
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aleksandrvk [35]

Answer:

Option three

Step-by-step explanation:

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2 years ago
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The ratio of the side lengths of a quadrilateral is 3:3:5:8, and the perimeter is 380cm. What is the measure of the longest side
MariettaO [177]

Answer: The second option (160 cm)

Step-by-step explanation:

1. You can obtain the perimeter of a quadrilateral by adding the lenghts of the sides.

2. You know that the ratio of the side lengths is 3:3:5:8 and the perimeter is 380 centimeters.

3. Therefore, you can write the following expression, where x is an integer:

3x+3x+5x+8x=380

4. Solve for x:

3x+3x+5x+8x=380\\19x=380\\x=\frac{380}{19}\\x=20

5. Therefore, the longest side is:

8x=8*20=160 (160 cm)

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3 years ago
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