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lubasha [3.4K]
3 years ago
14

Describe the slope of the line. Then find the slope (-2,-3) , (3,-3)

Mathematics
1 answer:
Vikentia [17]3 years ago
8 0
The slope would be 0 and it is a straight line line
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Describe a real world situauationthat could be modled by dividing two rational numbers
Dima020 [189]
You have 10 slices of cake, you and your friends Jerry, George, Martha, and Jenny ( just an example ) eat 2 slices of cake. 
A more real life one would be:
You have 6 bills to pay off, then two more come in, you only pay off 4, 
( I hope this helped, I'm sorry if any of this is wrong:) )
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3 years ago
  Express 35.4% as a decimal.
lakkis [162]
It is because the 35.4% divided the 100% total is B. 0.354
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3 years ago
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Give the domain and range.
Ymorist [56]

Answer:Graphs of inverse functions have a domain and range just like any other graph of a function. The domain of an inverse function is the range of the original, and the range of an inverse function is the domain of an original.

Step-by-step explanation:

7 0
3 years ago
A certain number was divided by 3 and 3 was added to the result. The final answer was 8 what was the number​
nevsk [136]

Answer:

15

Step-by-step explanation:

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5 0
2 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
3 years ago
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