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Gnesinka [82]
3 years ago
14

ANSWER QUICK BESTIES!! ty

Mathematics
2 answers:
anygoal [31]3 years ago
7 0

Answer:

Option B

Step-by-step explanation:

Option A, C and D have x- values that repeat and you cannot have that.

Y values can repeat but not x-values.

Option B has all x values with different y-values

erik [133]3 years ago
7 0

Answer:

B.

Step-by-step explanation:

an output can have more than one input but an input can only have one output

basically only one arrow can go from the input to the output and b is the only one who's graph thing is like that

hope this helps <3

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Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.
Bingel [31]

Answer:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

Step-by-step explanation:

For this case we want to find the following integral:

\int_{-\infty}^{-5} x^{-2}dx

And we can solve the integral on this way:

\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}

\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}

And if we evaluate the integral using the fundamental theorem of calculus we got:

\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}

Because the \lim_{x\to -\infty} \frac{1}{x} =0

The integral converges to \frac{1}{5}

8 0
3 years ago
Find the measure of &lt; AED for m &lt; BEC = 96
Strike441 [17]
I wish you would of put a picture but with what you gave me. if the angle is a straight line then you would just set it up like 96+x=180 bc a straight line ='s 180 and den subtract 96 from 180 which is 84 so x would = 84 if the angle is a supp. angle but til there's not a picture this might be wrong.
But i hope this helps have a nice nite!
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