Answer:
AC = 13.38 miles
BC = 12.65 miles
Where C is the fire location
Step-by-step explanation:
Two fire-lookout stations A and B are 14 miles apart.
The bearing of the fire from station A is Upper N 35 degrees E .
This implies that angle A = 90-35= 55°( reason because B is directly NE of A)
bearing of the fire from station B is N 30 degrees W.
This signifies that angle B is 90-30 =60°
Let's call the fire position C
Angle C = 180-60-55
Angle C= 65°
For Side AC
AB/sin C = AC/sin B
14/sin 65 = AC/sin 60
AC = 13.38 miles
For Side BC
BC/sin A = AB/sin C
BC = sin 55 * (14/sin 65)
BC = 12.65 miles
It’s 42 + 15w when simplified
Ywygdvd hdvsvehwjsgehegwvq
This can be translated into an algebraic expression as
K/5 - b.
