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nalin [4]
3 years ago
14

Please need help with one

Mathematics
1 answer:
natulia [17]3 years ago
7 0

the answer of m angle q is 77

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Hassan is cooking some rice the recipe says he needs 450 grams of rice for 6 people.how many kilograms of rice would he need for
gregori [183]

Answer:

so if we take 450 an divide it by 6 you get 75. So take 75 times 18 and you get 1,350 so he would need 1,350 kilograms of rice for 18 people

Step-by-step explanation:

hope this helps :D

4 0
2 years ago
Two square rooms have a total floor of 89m^2.one room is 3m longer each way than the other,find the dimensions of the rooms
Katen [24]
Thank you for posting your question here at brainly. Below is the solution. I hope the answer will help you.

<span> x ( x+4) = 45 </span>

<span>5m X 5m AND 8m X 8m 
</span>
5) x ( x+6) = 135 

<span>x^2 +6x -135 = 0 </span>

<span>( x-9) ( x+15) = 0 </span>

<span>x = 9 </span>

<span>ANSWER 9 & 15</span>

8 0
2 years ago
Read 2 more answers
How would you solve the equation 5x - 1 = 149?
PIT_PIT [208]

Answer:

30

Step-by-step explanation:

5x-1=149

5x=149+1=150

5x=150

x=150/5

x=30

3 0
2 years ago
Read 2 more answers
As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0
3 years ago
For (a)-(e), state the property of water that is significant, and give one example of that property is biological importance: (a
Diano4ka-milaya [45]
A) high transparency of visible light
significance= allows photosynthesis to happen and speed up chemical reactions

b) high cohesion because of hydrogen bonding
significance=  transport of water relies on water being pulled up around the plant.
4 0
3 years ago
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