2 years ago

Help i will mark brainliest

Mathematics

1 answer:

Yuki888 [10]2 years ago

5 0

Answer:

Whats the question

Step-by-step explanation:

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What two numbers add to be 6 and multiply to be 15

yarga [219]

$\displaystyle \bf \\
x_1+x_2=6\\\\
x_1\cdot x_2=15\\\\
\Longrightarrow~~x^2-6x+15=0\\\\
x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-60}}{2}=\\\\
=\frac{6\pm\sqrt{-24}}{2}=\frac{6\pm2\sqrt{-6} }{2}=3\pm i\sqrt{6}\\\\
x_1=\boxed{3-i\sqrt{6}}\\\\
x_2=\boxed{3+i\sqrt{6}}\\\\
\texttt{Verify:}\\\\
x_1+x_2=3-\underline{i\sqrt{6}}+3+\underline{i\sqrt{6}}=3+3=6~~correct\\\\
x_1\cdot x_2=(3-i\sqrt{6})(3+i\sqrt{6})=3^2-(i\sqrt{6})^2=9+6=15~~correct$

4 0

3 years ago

Can someone help me with this problem?

pashok25 [27]

No, it is not a solution.

Let's plug 5 into the equation where p is.

10(5) - 2 > 97

50 - 2 > 97

48 > 97

This is false, 48 is less than 97.

7 0

3 years ago

Read 2 more answers

Hi, I really need help with this question please, <br><br> dividing x^3+5x^2+x−2 by x + 3

MaRussiya [10]

3x+10x+x-2/x+3
14x-2/x+3
7(2x-1)/x+3

8 0