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cluponka [151]
3 years ago
9

8 less than a number is less than or equal to 17

Mathematics
1 answer:
Doss [256]3 years ago
4 0

Answer:

25

Step-by-step explanation:

25-8=17

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Can somebody check this and tell me if its wrong or right? ASAP
Mandarinka [93]

Answer:

Right

Step-by-step explanation:

8 0
2 years ago
A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data:
adoni [48]

Answer:

a.) the average speed of the aircraft in miles per hour

115.76 miles/ hour

b.) the fuel consumption in miles per pound of fuel

(assume a density of 0.70 g/mL for the fuel.)

2.8 miles/Ib of fuel

Step-by-step explanation:

A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data:

flight distance: 25,012 miles

flight time: 9 days, 3 min., 44 seconds

fuel capacity: nearly 9000 lbs.

fuel remaining at the end of flight: 14 gal.

To the maximum number of significant figure permitted, calculate:

a.) the average speed of the aircraft in miles per hour

Step 1

We convert the time to hours

flight time: 9 days, 3 min., 44 seconds

1 day = 24 hours

9 days =

24 × 9

= 216 hours

60 mins = 1 hour

3 mins =

3/60 = 1/20 = 0.05 hours

1 hour = 60 minutes

1 minute = 60 seconds

1 hour = 60 × 60 = 3600 seconds

If 3600 seconds = 1 hour

44 seconds =

= 44/3600

= 0.0122222222 hours

Total number of hours spent = (216 + 0.05 + 0.0122222222) hours

= 216.06222222 hours

Speed = Distance/Time

= flight distance: 25,012 miles

Speed = 25,012 miles/ 216.06222222hours

= 115.76294895 miles/ hour

Approximately = 115.76 miles/ hour

b.) the fuel consumption in miles per pound of fuel

(assume a density of 0.70 g/mL for the fuel.)

Step 1

We determine how much fuel is used

We have 14 gallons of fuel left over

1 gallon = 3.785 litres

14 gallons =

Cross Multiply

14 gallons × 3.785 liters/1 gallon

= 52.9958 liters

Note that density of fuel =

0.70 g/ml

1 gram / millilitre = 1 kilogram / litre

Hence, 0.7g/ml = 0.7 kg/L

Hence,the mass of fuel left = 52.9958 liters * 0.7 = 37.09706kg

1 kilogram = 2.205 pounds

37.09706kg =

37.09706kg × 2.205 pounds

= 81.7990173 lbs

Since the full capacity = 9000 lbs

The fuel used = 9000 - 81.7990173 lbs

= 8918.2009827 lbs

Hence, fuel consumption is

Distance/ amount of fuel used

25012/8918.2009827 lbs = 2.8046015164 miles/lb of fuel

Approximately = 2.8 miles/Ib of fuel

7 0
3 years ago
Consider the sequence 6, 11, 16, 21 . . . . What is the 50th term in this sequence?
Damm [24]

Answer:

251

Step-by-step explanation:

Tn=5n+1

e.g.T1=5(1)+1

=6

e.g.T2=5(2)+1

=11

e.g.T3=5(3)+1

=16

e.g.T4=5(4)+1

=21

Answer:T50=5(50)+1

=251

5 0
3 years ago
What the answer for this ? :/
goblinko [34]
Hello there! I can help you! In order to answer those questions, we need to plug in the values, based off of the variable.

g. Okay. We are solving b - 10. b = -8. When you subtract something from a negative number, the number is even lower. Let's add the numbers first and then put in the negative symbol. 8 + 10 is 18. Put the negative sign and you get -18. The difference is -18.

h. Now, we solve a - b. a = 5 and b = -8. Because we are subtracting a negative number from a positive, we have to add both numbers, which means the number gets bigger. Ignore the negative sign and add. 5 + 8 is 13. There. The sum is 13.

i. The problem is c - a. c = -9 and a = 5. So as explained on problem G, for this problem, ignore the negative symbol and add. 9 + 5 is 14. Plug in the negative sign to get -14. There. The difference is -14.
3 0
3 years ago
What are the solutions to the following system of equations? y=x^2+12x+30 and 8x-y=10
Ierofanga [76]
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:

8x-10 = x^2+12x+30

Group all terms together on the right side.  To do this, add -8x+10 to both sides.  Then 0 = x^2 +4x +40.  You must now solve this quadratic equation for x, if possible.  I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.

If you have a graphing calculator, please graph 8x-10  and  x^2+12x+30 on the same screen.  You will see two separate graphs that do NOT intersect.  This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
6 0
3 years ago
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