Question

In this exercise we will practice using loops to handle collections/containers. Your job is to write a program that asks the user to enter a sentence, then it counts and displays the occurrence of each letter.
Note: your program should count the letters without regard to case. For example, A and a are counted as the same.
Here is a sample run:
Enter a sentence: It's a very nice day today!
a: 3 times
c: 1 times
d: 2 times
e: 2 times
i: 2 times
n: 1 times
o: 1 times
r: 1 times
s: 1 times
t: 2 times
v: 1 times
y: 3 times
Notes:
The purpose of this problem is to practice using loops and collections/containers/strings.
Please make sure to submit a well-written program. Good identifier names, useful comments, and spacing will be some of the criteria that will be used when grading this assignment.
This assignment can be and must be solved using only the materials that have been discussed in class: loops, the index system, strings, lists and/or dictionaries. Do not look for or use alternative methods that have not been covered as part of this course.
How your program will be graded:
correctness: the program performs calculations correctly: 40%
complies with requirements (it properly uses loops, and containers/strings): 40%
code style: good variable names, comments, proper indentation and spacing : 20%
Language is python 3

Answer 1

Answer:

In Python:

chars = 'abcdefghijklmnopqrstuvwxyz'

letter = input("Sentence: ")

for i in range(len(chars)):

   count = 0

   for j in range(len(letter)):

       if chars[i] == letter[j].lower():

           count = count + 1

   if count > 0 :

       print(chars[i]+": "+str(count)+" times")

Explanation:

This initializes the characters of alphabet from a-z

chars = 'abcdefghijklmnopqrstuvwxyz'

This prompts the user for sentence

letter = input("Sentence: ")

This iterates through the initialized characters

for i in range(len(chars)):

This initializes count to 0

   count = 0

This iterates through the input sentence

   for j in range(len(letter)):

This compares the characters of the sentence with alphabet a-z

       if chars[i] == letter[j].lower():

If there is a match, count is incremented by 1

           count = count + 1

If there is an occurrence of character,

   if count > 0 :

The character and its count is printed

       print(chars[i]+": "+str(count)+" times")