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3 years ago

You would like to narrow your search on this topic.

Computers and Technology

2 answers:

igor_vitrenko [27]3 years ago

7 0

Answer: AND

Explanation: which combines words together to narrow a search

frozen [14]3 years ago

3 0

Answer:

Not

Explanation:

cause we are excluding keywords in a search

You might be interested in

"You have an interface on a router with the IP address of 192.168.192.10/29. Including the router interface, how many hosts can

SSSSS [86.1K]

Answer:

6 hosts can have IP addresses on the LAN attached to the router interface

Explanation:

Given IP address

=> 192.168.192.10/29

It has a subnet mask of /29 which means it has 3 host bits. This is calculated by subtracting 29 from 32(number of bits in an IPV4)

Since there are 3 host bits, the total number of possible addresses is given by

=> $2^{3}$ = 8 possible addresses.

Out of these 8 possible addresses, the first address will be the subnet id and the last address will be the broadcast address.

Therefore, there are only 6 addresses available for the hosts.

Hope this helps!

5 0

3 years ago

Write a program that would determine the day number in a non-leap year. For example, in a non-leap year, the day number for Dec

SOVA2 [1]

Answer:

In Python:

months = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]

daymonths = [31,28,31,30,31,30,31,31,30,31,30,31]

day = int(input("Day: "))

month = input("Month: ")

ind = months.index(month)

numday = 0

for i in range(ind):

numday+=daymonths[i]

numday+=day

print(numday)

Explanation:

This initializes the months to a list

months = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]

This initializes the corresponding days of each month to a list

daymonths = [31,28,31,30,31,30,31,31,30,31,30,31]

This gets the day from the user

day = int(input("Day: "))

This gets the month from the user

month = input("Month: ")

This gets the index of the month entered by the user

ind = months.index(month)

This initializes the sum of days to 0

numday = 0

This adds up the days of the months before the month entered by the user

for i in range(ind):

numday+=daymonths[i]

This adds the day number to the sum of the months

numday+=day

This prints the required number of days

print(numday)

Note that: Error checking is not done in this program

7 0

3 years ago

Carlos had 194 seeds and 11 flower pots he put the same number of seeds in each flower pot which is the best estimate for the nu

Inessa [10]

Answer:

20?

Explanation:

4 0

3 years ago

The software that requests mail delivery from the mail server to an Internet device is known as mail ____ software.

OleMash [197]

The software that requests mail delivery from the mail server to an Internet device is known as mail client software.

Explanation:

Mail client software is a form of communication in which electronic messages are created and transferred between two or multiple devices connected to a network series or stream.

8 0

2 years ago

A computer system uses passwords that are six characters and each character is one of the 26 letters (a-z) or 10 integers (0-9).

lesantik [10]

Question continuation

Determine the following probabilities:

a. P(A)

b. P(B)

c. P(A ∩ B)

d. P(A ∪ B)

Answer:

a. P(A) = 0.1389

b. P(B) = 0.1389

c. P(AnB) = 0.0193

d. P(AuB) = 0.2585

Explanation:

Given

Password length = 6

Letters (a-z) = 26

Integers (0-9) = 10

Total usable characters = 26 + 10 = 36

a. P(A) = Probability that a password begins with vowel (a,e,i,o,u)

Probability = Number of required outcomes/ Number of possible outcomes

Number of required outcomes = Number of vowels = 5

Number of possible outcomes = Total usable characters = 36

P(A) = 5/36

P(A) = 0.13888888888

P(A) = 0.1389

b. P(B) = Probability that the password ends with an even number (0,2,4,6,8)

Probability = Number of required outcomes/ Number of possible outcomes

Number of required outcomes = Number of even numbers = 5

Number of possible outcomes = Total usable characters = 36

P(B) = 5/36

P(B) = 0.13888888888

P(B) = 0.1389

c. P(AnB)

This means that the probability that a password starts with a vowel and ends with an even number

P(AnB) = P(A) and P(B)

P(AnB) = P(A) * P(B)

P(AnB) = 5/36 * 5/36

P(AnB) = 25/1296

P(AnB) = 0.01929012345

P(AnB) = 0.0193 ----_---- Approximately

d. P(AuB)

This means that the probability that a password either starts with a vowel or ends with an even number

P(AuB) = P(A) or P(B)

P(AuB) = P(A) + P(B) - P(AnB)

P(AuB) = 5/36 + 5/36 - 25/1296

P(AuB) = 335/1296

P(AuB) = 0.25848765432

P(AuB) = 0.2585 ----_---- Approximately

4 0

3 years ago