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2 years ago

9

Which expression is equivalent to four?

1 answer:

Usimov [2.4K]2 years ago

5 0

C because first you do ( 4+2 ) = 6 and 10 - 6 = 4

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What is the solution set for x2+25=0

Masja [62]

Step-by-step explanation:

${x}^{2} + 25 = 0 \\ \therefore {x}^{2} = - 25 \\ \therefore {x} = \sqrt{ - 25} \\ \therefore {x} = \pm\sqrt{ - 1 \times 25} \\ \therefore {x} = \pm \sqrt{ 25} \times \sqrt{ - 1} \\ \therefore {x} = \pm5 \: i \\ \therefore {x} = \{ - 5i, \: \: 5i \} \: \\ is \: the \: solution \: set.$

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2 years ago

Which of the following numbers is an integer 1.33333..., 5.2, 2/3,-3

kap26 [50]

Integers are whole numbers so the answer is -3

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3 years ago

A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approxima

Nimfa-mama [501]

Answer:

350 square feet

Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle= $20 ft\times 230 ft$

We know that

Area of rectangle ,A=xy

Differentiate

$dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y$

We have $\frac{\partial A}{\partial x}=y=230 ft$

$\frac{\partial A}{\partial y}=x=120$

$dx=\frac{12}{12}=1 ft$

1 ft=12 in

Because 6 in added in both side of breadth

dy= $\frac{12}{12}=1 ft$

Because 6 in added on both sides of length of rectangle

Substitute the values

$dA=230\times 1+120\times 1=350 ft^2$

Hence, the number of square feet of paint in the strip=350 square feet

7 0

3 years ago

Chelsea invested $5600 at a rate of 3.6% compounded quarterly. Write a compound interest function to model the situation. Then f

Agata [3.3K]

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2 years ago

which function has real zeros at x = −10 and x = −6? f(x) = x2 16x 60 f(x) = x2 − 16x 60 f(x) = x2 4x 60 f(x) = x2 − 4x 60

LiRa [457]

Answer:

Option A is correct

The function $x^2+16x+60$ has real zeroes at x =-10 and x =-6

Explanation:

Given: The real zeroes or roots are x = -10, and x = -6

To find the quadratic function of degree 2.

$x^2- (\alpha+\beta)x + \alpha\beta =0$ where α,β are real roots. ....[1]

Here, α= -10 and β= -6

Sum of the roots:

α+β = -10+(-6) = -10-6 = -16

Product of the roots:

αβ = (-10)(-6)= 60

Substitute these value in equation [1] we have;

$x^2-(-16)x+60 = x^2+16x+60$

Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;

$x^2+16x+60$

8 0

2 years ago

Read 2 more answers