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4 years ago

Which function is a quadratic function? a(x) = –2x^3 + 2x – 6 b(x) = 5x^3 + 8x^2 + 3 c(x) = –8x^2 + 3x – 5 d(x) = 6x^4 + 2x – 3

Mathematics

1 answer:

Sedaia [141]4 years ago

5 0

Answer:

c(x) = –8x^2 + 3x – 5 is a quadratic

Step-by-step explanation:

A quadratic function involves the 2nd power of x: x^2, and may (or may not) involve the 1st and zeroth power of x.

a(x) = -2x^3 is not a quadratic because of that exponent 3; in a quadratic, the highest power is always 2.

b(x) = 5x^3 + 8x^2 + 3 is not a quadratic for the same reason that a(x) is not a quadratic.

c(x) = –8x^2 + 3x – 5 is a quadratic: the highest power of x is x^2, the other powers are x^1 and x^0.

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What's the answer to this? Or how do I figure it out?

trapecia [35]

B.) 14/43
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14 + 8 +6 + 9 +6
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3 years ago

A line passes through the points (-2, 9) and (1, 3).

siniylev [52]

Answer:

slope = -2

y-intercept = 5

Step-by-step explanation:

1) Find slope:

$\frac{3-9}{1-(-2)}$ = $\frac{-6}{3}$ = -2

-2 = slope

2) Find y intercept trough point slope and slope-intercept forms

y - y1 = m (x - x1)

y - 9 = -2 (x + 2)

y - 9 = -2x -4

+ 9 + 9

y = -2x + 5

y = mx + b with b being the y-intercept

5 = y-intercept

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2 years ago

Determine any data values that are missing from the table, assuming that the data represent a linear function.

AleksAgata [21]

Answer:

Step-by-step explanation:

3 0

3 years ago

Use addition to solve the linear system of equations. Include all of your work in your final answer. $\left\{ \right.$ 3x-y=6

ad-work [718]

Answer:

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

Step-by-step explanation:

We need to solve the linear system of equations.

$3x-y=6 \\y=x-4$

We can write second equation y=x-4 as: $-x+y=-4$

Let:

$3x-y=6--eq(1)\\ -x+y=-4--eq(2)$

Now, Adding equation 1 and 2

$3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1$

So, we get x = 1

Now, put value of x in second equation to find value of y:

$y=x-4\\Put\:x=1\\y=1-4\\y=-3$

So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

4 0

3 years ago

I need help with three and four

mart [117]

Answer:

3: $a^{2}+2ab+b^{2}$

4: $8x^{3} -12x^{2}+6x-1$

Step-by-step explanation:

Question 3 can be re-written as:

$(a+b)(a+b)$

which equals:

$a^{2}+2ab+b^{2}$

Question 4 can be re-written as:

$(2x-1)(2x-1)(2x-1)$

Doing the first 2 brackets gives us:

$(4x^{2} -4x+1)(2x-1)$

Expanding these two:

$8x^{3} -4x^{2} -8x^{2} +4x+2x-1$

Simplifying it:

$8x^{3} -12x^{2}+6x-1$

4 0

2 years ago

Read 2 more answers