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Leni [432]
3 years ago
7

Molly had a $12 gift card to download music. She bought 8 songs that each cost the same amount. Write a variable equation, then

determine how much Molly paid for each song?
Mathematics
1 answer:
Ghella [55]3 years ago
4 0

Answer:

Molly paid for each song $1.5

Step-by-step explanation:

Let

x ------> amount that Molly paid for each song

we know that

The amount that Molly paid for each song multiplied by 8 is equal to the gift card value

so

The linear equation that represent this problem is

8x=12

Solve for x

Divide by 8 both sides

x=12/8

x=\$1.5

Molly paid for each song $1.5

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iogann1982 [59]

Answer:

x = 2    y = 0

Step-by-step explanation:

8 0
2 years ago
What is the area of this trapezoid?<br><br><br><br> Enter your answer in the box.
Anton [14]

Answer:

80

Step-by-step explanation:

5 0
2 years ago
What is 1/8-10(3/4-3/8x)+5/8x
cluponka [151]

Answer:

x = 59/35

Step-by-step explanation:

<u>Step 1:  Distribute</u>

1/8 - 10(3/4 - 3/8x) + 5/8x

1/8 - 30/4 + 30/8x + 5/8x

<u>Step 2:  Combine like terms</u>

1/8 - 30*2/4*2 - 30/8x + 5/8x

1/8 - 60/8 + 35/8x

-59/8 + 35/8x

<u>Step 3:  Solve for x</u>

-59/8 + 35/8x + 59/8 = 0 + 59/8

35/8x * 8/35 = 59/8 * 8/35

x = 59/35

Answer:  x = 59/35

4 0
3 years ago
Anyone know the answer?
uysha [10]
AB = CB
Because they are congruent
Therefore CB = 5.9
Given perimeter = 17
CB+BE+ED+DC = 17
5.9 + BE + 2.8 + 5.6 = 17
BE + 14.3 = 17
BE = 17 - 14.3
= 2.7
Hope I helped
If I did please give brainlest answer
Thanks
8 0
3 years ago
3) The average age of students at XYZ University is 24 years with a standard deviation of 8 years. Number of students at the uni
otez555 [7]

Answer:

0.1875

Step-by-step explanation:

σM=σ/√N

=8/√7500

=8/86.608

=0.092

Z=(x-μ)/σ/√N

=(25.5-36)/8/√7500

=-10.5/0.0092=-1141.304

Z score = -1.3125

=(27-36)/8/√7500 =

=9/0.0092=978.261

Z score= -1.125

-1.125-(-1.3125)=-1.125+1.3125)= 0.1875

The probability that the sample mean will be between 25.5 and 27 years

P(between 25.5 and 27) = 0.1875

3 0
2 years ago
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