I reccomend that you add an image or better explain what you want us to do.
Answer:
In disguise right arrow In Standard Form a, b and c
x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1
2(w2 − 2w) = 5 Expand (undo the brackets),
and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5
z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3
Step-by-step explanation:
sorry it took so long
Assuming width=diameter
diameter/2=radius
area=hpir^2
w=d=2
d/2=2/2=1=r
h=6
area=6pi1^2
area=6pi1
area=6pi
aprox pi=3.141592
area=18.85 cm³
