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3 years ago

1) O > 3x - 3-6 What is the answer

Mathematics

2 answers:

Alinara [238K]3 years ago

8 0

Answer:

Step-by-step explanation:

I never seen that kind of question

creativ13 [48]3 years ago

7 0

Answer:

x<3

Step-by-step explanation:

Let's solve your inequality step-by-step.

0>3x−3−6

Step 1: Simplify both sides of the inequality.

0>3x−9

Step 2: Flip the equation.

3x−9<0

Step 3: Add 9 to both sides.

3x−9+9<0+9

3x<9

Step 4: Divide both sides by 3.

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Step-by-step explanation:

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3 years ago

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3 years ago

The value of an investment A (in dollars) after t years is given by the function A(t) = A0ekt. If it takes 10 years for an inves

Ludmilka [50]

Answer:

20 years.

Step-by-step explanation:

We have been given a formula $A(t)=A_0\cdot e^{kt}$ , which represents the value of an investment A (in dollars) after t years.

Substitute the given values:

$\$3,000=\$1,000\cdot e^{k*10}$

Let us solve for k.

$\frac{\$3,000}{\$1,000}=\frac{\$1,000\cdot e^{k*10}}{\$1,000}$

$3=e^{k*10}$

Take natural log of both sides:

$\text{ln}(3)=\text{ln}(e^{k*10})$

Using property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$\text{ln}(3)=10k\cdot\text{ln}(e)$

We know that $\text{ln}(e)=1$ , so

$\text{ln}(3)=10k\cdot 1$

$\text{ln}(3)=10k$

$\frac{\text{ln}(3)}{10}=\frac{10k}{10}$

$\frac{\text{ln}(3)}{10}=k$

$\$9,000=\$1,000\cdot e^{\frac{\text{ln}(3)}{10}*t}$

Dividing both sides by 1000, we will get:

$9=e^{\frac{\text{ln}(3)}{10}*t}$

Take natural log of both sides:

$\text{ln}(9)=\text{ln}(e^{\frac{\text{ln}(3)}{10}*t)$

$\text{ln}(9)=\frac{\text{ln}(3)}{10}*t\cdot\text{ln}(e)$

$\text{ln}(9)=\frac{\text{ln}(3)}{10}*t\cdot1$

$10*\text{ln}(9)=10*\frac{\text{ln}(3)}{10}*t$

$10\text{ln}(9)=\text{ln}(3)*t$

$10\text{ln}(3^2)=\text{ln}(3)*t$

$2\cdot 10\text{ln}(3)=\text{ln}(3)*t$

$20\text{ln}(3)=\text{ln}(3)*t$

Divide both sides by $\text{ln}(3)$ :

$\frac{20\text{ln}(3)}{\text{ln}(3)}=\frac{\text{ln}(3)*t}{\text{ln}(3)}$

$20=t$

Therefore, it will take 20 years for the investment to be $9,000.

5 0

3 years ago

Marcy purchases a total of 12 adult, child, and senior tickets for an art museum tour. Adult tickets are $5 each, child tickets

Kruka [31]

Answer:

A: The solution to this system is no viable because it results in fractional values of tickets

Step-by-step explanation:

Let number of adult, child, and senior tickets be x, y and z respectively.

Thus;

x + y + z = 12 - - - (eq 1)

she purchases 4 more child tickets than senior tickets.

Thus, y = z + 4

Thus:

x + (z + 4) + z = 12

x + 2z + 4 = 12

x + 2z = 8 - - - (eq 2)

Also, We are told that Adult tickets are $5 each, child tickets are $2 each, and senior tickets are $4 each. She spends a total of $38,

Thus;

5x + 2(z + 4) + 4z = 38

5x + 2z + 8 + 4z = 38

5x + 6z + 8 = 38

5x + 6z = 38 - 8

5x + 6z = 30

Divide through by 5 to get;

x + (6/5)z = 6 - - - (eq 3)

Subtract eq 2 from eq 1 to get;

2z - (6/5)z = 8 - 6

2z - (6/5)z = 2

Multiply through by 5 to get;

10z - 6z = 10

4z = 10

z = 2½

It's not possible to have a fractional value of a ticket and thus we can say that the solution is not viable.

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3 years ago

PLEASE HELP ME!!!! I really need to get a good grade on this assignment I WILL give brainly points

NemiM [27]

The answer is true. It does increase

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3 years ago