Question

Solve this step by step using the quadratic function y=x^2 +x+2

Answer 1

Answer:

x=+$\frac{\sqrt{4y-7}-1 }{2}$

Step-by-step explanation:

Quadratic function =( -b+$\sqrt{b^2+4ac}$  )/2a

x^2+x+2-y=0

x=-1+$\sqrt{1^2-4(2-y)}$ /2

x=-1+$\sqrt{4y-7}$ /2

x=+ $\frac{\sqrt{4y-7}-1 }{2}$

Pretty sure this is right. Would appreciate a brainliest