Question

find the 17th term of the arithmetic sequence whose common difference is d=3 and whose first term is a1=1.

Answer 1

Answer:

$a_{17} = 49$

Step-by-step explanation:

Given

Sequence: Arithmetic

$d = 3$

$a_1 = 1$

Required

Determine the 17th term

The nth term of an arithmetic sequence is:

$a_n = a_1 + (n - 1) d$

In this case: n = 17

So, we have:

$a_{17} = 1 + (17 - 1) * 3$

$a_{17} = 1 + 16 * 3$

$a_{17} = 1 + 48$

$a_{17} = 49$

Hence, the 17th term is 49