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SIZIF [17.4K]
2 years ago
13

Worth 20 points

Mathematics
1 answer:
bezimeni [28]2 years ago
5 0

Answer:

1. 1/8 ÷ 3/4 = 1/6

2. 3/5 ÷ 3/2 = 2/5

3. 4/1 ÷ 2/3 = 6

4.9/4 ÷ 6/5 = 15/8

5.22/4 ÷ 2/5 = 261/80

Step-by-step explanation:

Hope this Helped

You might be interested in
Suppose that $7,000 is invested at an interest rate of 6%, compounded continuously. Find the amount in the account after five ye
Goshia [24]

Answer:

9100

Step-by-step explanation:

I=Prt

I=7,000(.06)5

I=420(5)

I=2,100

2,100+7,000=9,100

7 0
3 years ago
Read 2 more answers
Los siguientes problemas se encuentran en lenguaje común, traduzcan cada uno de ellos a lenguaje algebraico solamente. AEel cuad
dsp73

Answer:

A) La traducción algebraica de la oración es x^{2}-5=220.

B) La traducción algebraica de la oración es 4\cdot x^{2} = 100.

C) Ese problema se traduce bajo esta forma lógica como w\cdot l = 5625\,m^{2} \land w = l \implies w = 75\,m \land l = 75\,m.

Step-by-step explanation:

Debemos proceder en este ejercicio como sigue:

1) <em>Leer cuidadosamente la frase.</em>

2) <em>Escribir su equivalente matemático a medida que se lee y hasta culminarlo.</em>

A continuación, presentamos el desarrollo y la conclusión de cada ejercicio:

A) Interpretamos la oración paso a paso conforme al lenguaje matemático conocido:

(i) <em>El cuadrado de un número</em>:

x^{2}

(ii) <em>El cuadrado de un número menos cinco</em>:

x^{2}-5

(iii) <em>El cuadrado de un número menos cinco es igual a</em>:

x^{2}-5=

(iv) <em>El cuadrado de un número menos cinco es igual a doscientos veinte</em>:

x^{2}-5=220

La traducción algebraica de la oración es x^{2}-5=220.

B) Interpretamos la oración paso a paso conforme al lenguaje matemático conocido:

(i) <em>Alejandra pensó un número</em>:

x

(ii) <em>Alejandra pensó un número, lo elevó al cuadrado,</em>:

x^{2}

(iii) <em>Alejandra pensó un número, lo elevó al cuadrado, multiplicó el resultado por cuatro</em>:

4\cdot x^{2}

(iv) <em>Alejandra pensó un número, lo elevó al cuadrado, multiplicó el resultado por cuatro y obtuvo cien</em>:

4\cdot x^{2} = 100

La traducción algebraica de la oración es 4\cdot x^{2} = 100.

C) Interpretamos la oración paso a paso conforme al lenguaje matemático conocido:

(i) <em>Si una pista de baile tiene un área de 5625 m²</em>:

A = 5625\,m^{2}

(ii) <em>Si una pista de baile tiene un área de 5625 m² y se sabe que su ancho mide lo mismo que su ancho</em>:

Lo que se infiere de la afirmación es que la pista de baile sería un cuadrilátero y más precisamente, un cuadrado:

A = 5625\,m^{2}

A = w\cdot l (l - Largo, w - Ancho)

w = l

Entonces la ecuación algebraica sería:

l^{2} = 5625\,m^{2}

(iii) Si una pista de baile tiene un área de 5625 m² y se sabe que su ancho mide lo mismo que su ancho, cuanto medirán las dimensiones de la pista de baile:

Lo que se infiere de la afirmación es que la pista de baile sería un cuadrilátero y más precisamente, un cuadrado:

A = 5625\,m^{2}

A = w\cdot l (l - Largo, w - Ancho)

w = l

Entonces la ecuación algebraica sería:

l^{2} = 5625\,m^{2}

Y obtenemos la longitud por despeje:

l = \sqrt{5625\,m^{2}}

l = 75\,m

w = 75\,m

Ese problema se traduce bajo esta forma lógica como w\cdot l = 5625\,m^{2} \land w = l \implies w = 75\,m \land l = 75\,m.

4 0
3 years ago
HELP<br> ME I AM CRYING SO MUCH ALSO LMK IF U CANT SEE
Wittaler [7]
Send a better picture so I can help.
3 0
3 years ago
How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

7 0
3 years ago
5 Divided by (1200+700)
solmaris [256]

Answer:

380

Step-by-step explanation:

1200 + 700 = 1900/5 = 380

7 0
3 years ago
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