Question

The population of a city in 2000 was 18,500 people. Since then the population has increased 4.8% every year. Determine the correct equation that would represent what the population would be in the year 2028.

Answer 1

Answer:

see below

Step-by-step explanation:

Consider the year 2000 to be year 0. This would make year 2028 year 8.

Population growth or decay function: $A = Pe^{rt}$

where A is the final amount, P is the principal amount, r is the rate, and t is time.

$A = 18,500e^{(0.048)(8)}$

This can be simplified to

$A = 18,500e^{0.384}$

Hopefully this is what the question is asking!