Answer:
X = 14,700
Step-by-step explanation:
you can use a calculator to get the x.
X=3816371/(27×63)
A parallelogram has symmetry wii respect to the line that C- Bisects it from opposite vertices.
All the others are never true for a parallelogram. You can try cutting out a parallelogram and folding it to see for yourself!
Hope this helps!!
H is the number of hours worked. So the expression 200h+250 is 200 times the number of hours plus 250.
Here's a few computations using different values for h
1 hour --> (200)(1)+250 = 450
2 hours --> (200)(2) + 250 = 650
3 hours --> (200)(3)+250 = 850
10 hours --> (200)(10)+250 = 2250
As you can see the 250 is fixed. It gets added to the cost no matter how many hours the lawyer works. This is most likely a flat fee. Just to meet the lawyer you pay $250.
The 200 gets multiplied by the hours worked. So the 200 is an hourly rate. The more hours the lawyer works, the more he gets paid because this part of the expression depends on the hours worked.
Thus, an interpretation of the expression 200h + 250 is that the lawyer charges a fee of $250 per consultation and an additional $200 per hour on top of that.
Answer:
45%
Step-by-step explanation:
There are 5 A's out of a total of 11 letters which is 5/11. 5/11 as a decimal is 0.45 which, as a percentage, is 45%
The expected length of code for one encoded symbol is
where 
is the probability of picking the letter 
, and 
is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length 
, we would then expect ![E[L]=1.375n](https://tex.z-dn.net/?f=E%5BL%5D%3D1.375n)
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get ![\mathrm{Var}[L]=1.859n](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3D1.859n)
.
