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Mumz [18]
3 years ago
9

Fran and 8 friends must share 3 liter of water. how get?​

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0
Each friend would get about 12.7 ounces of water.
pav-90 [236]3 years ago
5 0
The answer would be that each friend would 12.7 ounces
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Construct an inscribed circle in triangle PQR by finding the incenter of the triangle.
hodyreva [135]

Answer:

Check it below

Step-by-step explanation:

Hello!

By definition, the intercept of the 3 bisectors, within a triangle is the Incenter. So let's get started, by tracing three bisectors.

In the triangle PQR::

  1. Use a compass, open its legs with a little more than half of \overline{PQ}  . Place the needle point in the vertex of P. Mark!
  2. Do the same, placing the needle point in Q, following \overline{QP} direction. Mark
  3. Repeat it with the other triangle's line segment, namely:

\overline {QR},\:\overline{PR}

   4.Trace with a ruler, from each intersection point a line. You'll trace three lines then.

    5. Place the compass' needle point in this intersection point, (inside the triangle) with a hinge up to the triangle side, draw the circle inscribed.

 

7 0
3 years ago
If line segments A and B are parallel, which of the following pairs of angles are not equal?
anyanavicka [17]

Answer:

C: ∠6 and ∠2

Step-by-step explanation:

Step 1:

∠6 = ∠9        S.S. Int. ∠'s      (Same Side Interior ∠'s)

Step 2:

∠9 + ∠2 = 180°        Sum of line

Step 3:

∠9 ≠ ∠2

Answer:

C: ∠6 and ∠2

Hope This Helps :)

4 0
3 years ago
Read 2 more answers
2) 83,97,85,84,96, 80,80,87,91<br> Mean median and mode
marusya05 [52]

\text {Hi! Let's Solve this Problem!}

\text {Before you find the Mean, Medina and Mode you must put the numbers in order.}

\text {Before: 83, 97, 85, 84, 96, 80, 80, 87, 91}\\\text {After: 80, 80, 83, 84, 85, 87, 91, 96, 97}

\underline {\text {Mean}}

\text {To Find the Mean you must Add all the Numbers then Divide.}

\text {Add:} \text 80+80+83+84+85+87+91+96+97=\fbox {783}}

\text {Divide:} \text {783/9=}

\text {The Mean Is:}

\fbox {87}

\underline {\text Median}}

\text {To find the Median you find the number that's in the middle of the set.}

\text {Put your Left Pointer Finger on 83. Put your Right Pointer Finger on 91.}

\text {Move your Left Finger to the Right. Move your Right Finger to the Left.}

\text {Once your Left Finger makes it to 84 and your Right Finger makes it to 87} \text {it shows that 85 is left in the middle.}

\text {The Median Is:}

\fbox {85}

\underline {\text {Mode}}

\text {Finding the Mode means finding the number} \text { that shows the most in the number set given.}

\text {Since 80 is the number that is showing more than any other number} \text {this tells us that 80 is our Mode.}

\text {The Mode Is:}

\fbox {80}

\text {Best of Luck!}

4 0
3 years ago
The first side of a triangle is 7cm less than twice the second side. The third side is 4cm longer than the first side. The perim
Vinil7 [7]

Given:

First side(A): 2B - 7

Second side(B): B

Third side(C): B + 4

Plug in values:

A + B + C = 80

2B - 7 + B + B + 4 = 80

If you look at the coefficients only, you can rewrite the equation like this:

2B + B + B - 7 + 4 = 80

This means that 4B - 7 + 4 = 80

=4B - 3 = 80

= 4B = 80 + 3

B = 83/4, so you can either write B as 83/4 or as 20.75.

Checking your work:

A: 2(20.75) - 7 = 34.5

B: 20.75

C: 4 + 20.75 = 24.75

34.5 + 20.75 + 24.75 = 80cm.

Hope this helped.

3 0
2 years ago
Ashley bought 2 CD's for $15 each and a charger for 7.50. If she writes a check for $45.94, What is the sales tax rate?
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I don’t think y’all should click on that link-
7 0
2 years ago
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