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Eddi Din [679]
3 years ago
12

PLEASE HELP!!! I WILL GIVE BRAILIEST

Mathematics
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

1) if b = 5

Answer: never a repeating decimal.

2) if b = 6

Answer: sometimes a repeating decimal

3) if b = 7

Answer: Always a repeating decimal

4) if b = 8

Answer: Sometimes a repeating decimal

5) if b = 9

Answer: Always a reapeating decimal.

Step-by-step explanation:

1) if b = 5

Answer: never a repeating decimal.

2) if b = 6

Answer: sometimes a repeating decimal

3) if b = 7

Answer: Always a repeating decimal

4) if b = 8

Answer: Sometimes a repeating decimal

5) if b = 9

Answer: Always a reapeating decimal.

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Answer:

d:-12,0

Step-by-step explanation:

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3 years ago
What is the value of the correlation coefficient r of the data set?
enyata [817]

The correct option will be:  C) 0.84

<u><em>Explanation</em></u>

Formula for Correlation coefficient :

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}

First, for each point(x, y), we need to calculate x², y² and xy .

Then, we will find sum all x, y, x², y² and xy, which gives us Σx, Σy, Σx², ∑y² and Σxy

<em>(Please refer to the attached image for the table )</em>

Here we got, ∑x = 44 , ∑y = 183 , ∑x² = 362 , ∑y² = 6575 and ∑xy = 1480

'n' is the total number of data set, which is 7 here.

So, plugging those values into the above formula..........

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}\\ \\ r=\frac{7(1480)-(44)(183)}{\sqrt{[7(362)-(44)^2][7(6575)-(183)^2]}}\\ \\ r=\frac{10360-8052}{\sqrt{(598)(12536)}}\\ \\ r=\frac{2308}{\sqrt{7496528}}\\ \\ r=0.84

So, the value of the correlation coefficient is 0.84

4 0
3 years ago
Read 2 more answers
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Hope This Helps!
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