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kotykmax [81]
3 years ago
14

729 ÷ 0.9Do the solutionIf its right i will makeYou the brainliest

Mathematics
1 answer:
anyanavicka [17]3 years ago
4 0

Answer:

Here's your ans

hope it helps you

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Which expression has the least value?<br> A. 3(33)<br> B. 0 31-33)<br> C. 0-31-33)<br> D. 3(3-3)
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Answer:

I think it is C but can't be sure because B isn't clear.

Step-by-step explanation:

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Look at the image below.<br> 10<br> 11 8<br> Find the area of the parallelogram.<br> square units
Rus_ich [418]

Edit: Misread the diagram, the previous answer was wrong.

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Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Hint: the
Julli [10]

Answer:

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. 16)n = 182, x = 135; 95 percent

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6 0
3 years ago
Mel's Furniture received an invoice dated September 27 for 5 bedroom sets at $3,000 each. The invoice indicated a chain discount
LenKa [72]

Answer: $12,916.70

Step-by-step explanation:

Given the following:

Invoice received :

Bedroom set = 5

Cost per set = $3,000

Chain discount = 5/8/3

Freight cost = $200

If Mel pays within the discount period:

Chain discount given = 5/8/3

Therefore, net equivalent price rate equals:

(1 - 0.05) × (1 - 0.08) × (1 - 0.03) =

0.95 × 0.92 × 0.97 = 0.84778

Net price = total cost × 0.84778

($3000 × 5) × 0.84778

$15000 × 0.84778 = $12,716.7

Net equivalent price + FOB Shipping

$12,716.7 + $200 = $12,916.70

5 0
4 years ago
This is my last question can someone help me with my homework.
shutvik [7]

9514 1404 393

Answer:

  C, A, A

Step-by-step explanation:

In general, you ...

  • identify the coefficients of one of the variables
  • swap them, and negate one of them
  • multiply the corresponding equations by the "adjusted" coefficients.

__

In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:

  multiply equation 2 by -4 . . . (eliminates x)

Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:

  multiply equation 1 by 3 . . . (eliminates y)

These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.

__

The other problems are worked in a similar fashion.

8 0
3 years ago
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