For the first line we have a slope of (y2-y1)/(x2-x1)
(2--2)/(1--1)=4/2=2 so we have:
y=2x+b, now solve for b with either of the points, I'll use: (1,2)
2=2(1)+b
b=0 so the first line is:
y=2x
Now the second line:
(1-10)/(4--2)=-9/6=-3/2 so far then we have:
y=-3x/2+b, using point (4,1) we solve for b...
1=-3(4)/2+b
1=-6+b
b=7 so
y=-3x/2+7 or more neatly...
y=(-3x+14)/2
...
The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...
2x=(-3x+14)/2
4x=-3x+14
7x=14
x=2, and using y=2x we see that:
y=2(2)=4, so the solution occurs at the point:
(2,4)
False, it would not make a right triangle
The value of the y coordinate of any point on the x axis is always 0.
<u><em>Explanation</em></u>
Suppose, the co ordinate of any point is
.
It means, the distance of the point from x-axis is '
' and distance from y-axis is '
'.
Now if the point lies on the x-axis, that means the distance of the point from x-axis will be 0. Thus, the value of '
' will be 0.
So, the value of the y coordinate of any point on the x axis is always 0.
Answer:
The answer is
, or the first option.
The last option isn't correct for this answer, even though it is correct mathematically. This is because it wants the fully simplified version, so the 5o squared would turn into a 5 and a 2, with the 5 multiplying the -6, and the 2 remaining underneath the square root.
#teamtrees #WAP (Water And Plant)
Answer:
Step-by-step explanation: