What do you mean by "solve this?" Until you set f(x) = to some constant number, you don't have an equation and thus can't expect to find solutions.
Why don't we take <span>3x^2-18x+27 and set it = to 0, and only then try to solve this equation?
</span><span>3x^2-18x+27 = 0. Dividing both sides by 3, we get x^2 - 6x + 9= 0, which can be factored as
(x-3)^2 = 0. Taking the sqrt of both sides, we get x-3 = 0. Actually, there are 2 roots: 3 and 3. Again, this statement is true only if we set </span><span>3x^2-18x+27 = to 0.</span>
Just have to use cosine rule!!! :)
this is for the Sin
*Remember that sin = opposite / hypotenuse*
a² + b² = c² (where a and b are legs and c is the hypotenuse)
From the picture, you can see:
a = 3
c = 4
Plug these into the equation and solve for b.
* a² + b² = c² *
step 1: 3² + b² = 4²
step 2: 9 + b² = 16
step 3: b² = 16 - 9
step 4: b² = 7
step 5: √(b²) = √7
step 6: b = ± √7
FOR COS:
From the picture, you can see that if θ is in quadrant II, b has to be negative.
b = -√7 = adjacent
Remember that cos θ = adjacent / hypotenuse.
cos θ = adjacent / hypotenuse
cos θ = (-√7 / 4)
Answer:
Step-by-step explanation:
i assume you need x
-3+9x=-6
add 3 on both sides
9x=-6+3
9x=-3
x=-3/9=-1/3
