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Stels [109]
3 years ago
13

Solve for brainliest and all my points

Mathematics
1 answer:
inessss [21]3 years ago
6 0

Answer:

b = 6 units

Step-by-step explanation:

Area = 1/2bh

8 = 1/2(b)(8/3)

divide both sides by 1/2

16 = b(8/3)

multiply both sides by 3

48 = 8b

divide both sides by 8

b = 6 units

For your boxes:

1/2 x b/1 x 8/3 = 8/1

b/1 x 8/3 = 16/1

8b/3 / 8 = 2/1

b/3 x 3 = 6

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I need help on this problem
Arte-miy333 [17]

Answer: QR=4.04

Step-by-step explanation:

For this exercise you must use the followinG Trigonometric Identity:

tan\alpha=\frac{opposite}{adjacent}

In this case, given the right triangle PQR, you can identify that:

\alpha=60\°\\opposite=PR=7.0\\adjacent=QR

Then, the  next step is to substitute those values into tan\alpha=\frac{opposite}{adjacent}:

tan(60\°)=\frac{7.0}{QR}

And the final step is to solve for "QR" in order to find its value.

So you get that this is:

(QR)(tan(60\°))=7.0\\\\QR=\frac{7.0}{tan(60\°)}\\\\QR=4.04

6 0
3 years ago
4, 2, 4, 1, 8, 9, 7, 5, 2, 8
Oxana [17]

Answer:

0

Step-by-step explanation:

The range is the difference between the lowest and highest values. Since 9 is still the highest value, the range would not change by any amount by replacing 7 with 9.

4 0
3 years ago
What is the explicit formula for this sequence?
andreev551 [17]

Answer:

D

Step-by-step explanation:

This is an arithmetic sequence with n th term

a_{n} = a + (n - 1)d

where a is the first term and d the common difference

d = - 2 - (- 6) = 2 - (- 2) = 6 - 2 = 4 and a = - 6, hence

a_{n} = - 6 + (n - 1)4 → D

8 0
3 years ago
The hypotenuse of a right triangle measures 2 sqrt 15 centimeters and its shorter leg measures 2 sqrt 6
ioda

Answer: please see the attachments for the solution.

Step-by-step explanation:

3 0
4 years ago
Your running a fuel economy study. You find a blue car. It travels 44 1/2 miles on 1 1/4 gallons of gasoline another car is red
frozen [14]

Given:

Blue car travels 44\dfrac{1}{2} miles on 1\dfrac{1}{4} gallons of gasoline.

Red car travels 20\dfrac{4}{5} miles on \dfrac{4}{5} gallons of gasoline.

To find:

The unit rate for miles per gallon for each car and find which car could travel the greatest distance on one gallon of gasoline.

Solution:

We know that,

\text{Unit rate}=\dfrac{\text{Total distance covered by the car}}{\text{Number of gallons of gasoline}}

Using this formula, the unit rate of blue car is

\text{Unit rate of blue car}=\dfrac{44\dfrac{1}{2}}{1\dfrac{1}{4}}

\text{Unit rate of blue car}=\dfrac{\dfrac{88+1}{2}}{\dfrac{4+1}{4}}

\text{Unit rate of blue car}=\dfrac{89}{2}\times \dfrac{4}{5}

\text{Unit rate of blue car}=\dfrac{178}{5}

\text{Unit rate of blue car}=35.6

Unit rate of red car is

\text{Unit rate of red car}=\dfrac{20\dfrac{4}{5}}{\dfrac{4}{5}}

\text{Unit rate of red car}=\dfrac{\dfrac{100+4}{5}}{\dfrac{4}{5}}

\text{Unit rate of red car}=\dfrac{104}{5}\times \dfrac{5}{4}

\text{Unit rate of red car}=26

Therefore, the unit rate of blue car is 35.6 miles per gallon of gasoline and  unit rate of red car is 26 miles per gallon of gasoline.

Since, unit rate of blue car is greater than the red car, therefore blue car travel the greatest distance on one gallon of gasoline.

5 0
3 years ago
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