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UkoKoshka [18]
3 years ago
15

let x represent one number and let y represent the other number. use the given conditions to write a system of equations. solve

the system and find the numbers. three times a first number decreased by a second number is 22. the first number increased by twice the second number is 12.
Mathematics
1 answer:
kiruha [24]3 years ago
7 0

9514 1404 393

Answer:

  (x, y) = (8, 2)

Step-by-step explanation:

The relevant equations are ...

  3x -y = 22

  x +2y = 12

__

We can eliminate y by adding twice the first equation to the second.

  2(3x -y) +(x +2y) = 2(22) +(12)

  7x = 56

  x = 8

Substituting into the first equation gives ...

  3(8) -y = 22

  y = 24 -22 = 2

The first number is 8; the second number is 2.

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\huge\textsf{Hey there!}

\mathsf{2x^2 + 3x - 12}

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