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UkoKoshka [18]
3 years ago
15

let x represent one number and let y represent the other number. use the given conditions to write a system of equations. solve

the system and find the numbers. three times a first number decreased by a second number is 22. the first number increased by twice the second number is 12.
Mathematics
1 answer:
kiruha [24]3 years ago
7 0

9514 1404 393

Answer:

  (x, y) = (8, 2)

Step-by-step explanation:

The relevant equations are ...

  3x -y = 22

  x +2y = 12

__

We can eliminate y by adding twice the first equation to the second.

  2(3x -y) +(x +2y) = 2(22) +(12)

  7x = 56

  x = 8

Substituting into the first equation gives ...

  3(8) -y = 22

  y = 24 -22 = 2

The first number is 8; the second number is 2.

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Step-by-step explanation:

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I need help. Please
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Answer:

Answer is A.

Step-by-step explanation:

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The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

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5 0
2 years ago
A fisherman uses a spring scale to weigh a tilapia fish. He records the fish weight as a kilograms and notices that the spring s
belka [17]

Answer:

k = \frac{980a}{b}

Step-by-step explanation:

Fisherman noticed a stretch in the spring = 'b' centimetres

Weight of the fish = a kilograms

If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,

F = kΔx

Where k = spring constant

Δx = stretch in the spring

F = weight applied

F = mg

Here 'm' = mass of the fish

g = gravitational constant

F = a(9.8)

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Δx = b centimetres = 0.01b meters

Therefore, 9.8a = k(0.01b)

k = \frac{9.8a}{0.01b}

k = \frac{980a}{b}

Therefore, spring constant of the spring will be determined by the expression, k = \frac{980a}{b}

4 0
3 years ago
Find (f+g)(x).
kaheart [24]

Answer:

(f+g)(x)  = x^3 - 3x + 2

Step-by-step explanation:

Find  (f+g)(x) by adding together f(x) = -3x + 2   and  g(x) = x^3:

  (f+g)(x) = -3x + 2 + x^3, or, in standard form,

(f+g)(x)  = x^3 - 3x + 2                                                        

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