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Anettt [7]
3 years ago
10

1.give the sequence 8.5.2.-1,...at what term will the number become -25? A.11th term B.10th term C.12th term D.20th term 2.which

of the following is an algebraic esprression? A.3+5 B.n-1-14 C.3+5=8 D.x=53 3.what is the sum of the first 5 even numbers? A.30 B.20 C.10 D.50
Mathematics
1 answer:
Nitella [24]3 years ago
6 0

Answer: 1. C(12) 2. B(n-1-14) 3. A(30)

Step-by-step explanation: For number one the nth term with common difference d and first term a is a+(n-1)d=nth term, plug in the values you have and solve for n to get 12. For number 2 an algebraic expression has a variable and a constant but doesn't have an equal sign. So it is B. For number three just add them up. Hope this helped!  

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Fertilization takes place when: a sperm cell joins an egg a sperm cell starts developing an egg starts growing an egg is laid
andreev551 [17]

Answer:

1st option: when a sperm joins an egg

Step-by-step explanation:

A sperm will be accepted into the egg, and fertalize it

3 0
3 years ago
Please help me someone ASAP
Artyom0805 [142]
The Answer is b. Hope that helps
5 0
3 years ago
When Ginny hikes Mount Adams, she always packs a ratio of 20 protein bars to 15 water bottles in her backpack. How many protein
Yuliya22 [10]
If you divide it by 5 on both numbers you get four and three.  So 4 is the answer.
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4 years ago
If b = 5, what is b to the square root of 3
liubo4ka [24]
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6 0
3 years ago
What equation best models this data?(use y to represent the population of rabbits and t to represent the year, assuming that 201
liraira [26]

If we see the data closely, a pattern emerges. The pattern is that the ratio of the population of every consecutive year to the present year is 1.6

Let us check it using a couple of examples.

The rabbit population in the year 2010 is 50. The population increases to 80 the next year (2011). Now, \frac{80}{50}=1.6

Likewise, the rabbit population in the year 2011 is 80. The population increases to 128 the next year (2012). Again, \frac{128}{80}=1.6

We can verify the same ratio with all the data provided.

Thus, we know that the population in any given year is 1.6 times the population of the previous year. This is a classic case of a compounding problem. We know that the formula for compounding is as:

F=P\times r^n

Where F is the future value of the rabbit population in any given year

P is the rabbit population in the year "0" (that is the starting year 2010) and that is 50 in this question. (please note that there is just one starting year).

r is the ratio multiple with which the rabbit population increases each consecutive year.

n is the nth year from the start.

Let us take an example for the better understanding of the working of this formula.

Let us take the year 2014. This is the 4th year

So, the rabbit population in 2014 should be:

F_{2014} =50\times(1.6)^4\approx328

This is exactly what we get from the table too.

Thus, F=P\times r^n aptly represents the formula that dictates the rabbit population in the present question.

4 0
3 years ago
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