1) to this case you must match both equations
3x+2 = 2x-3 ⇒3x-2x = -3-2⇒x= -5
now the value of x substitute it in the any of two equations, y = 3(-5)+2 = -13
and the other equation is the same value
y = 2(-5)-3 = -13
the point is ( -5,-13)
solution is first os all find median
median is( 45+61)/2=53
find median of no in left of 53
it is 37
find median of no in right of 53
it is 64
now interquartile range=64-53=27
Simplified: -6m-6
Factored: 6(m+1)
