Answer:
6
Step-by-step explanation:
I wrote it super fast. lol
can you get it?
Answer:
For number 1, you draw a line to the middle graph
For number 2, you draw a line to the bottom graph
For number 3, you draw a line to the top graph.
Step-by-step explanation:
To figure out where the graph goes, you only need to know if the point is on the graph. For the top graph, you know that the point 2,2 is on the graph so that means one part of the graph has to be 2 and 2. The x has to equal to and the y is equal 2. Therefore, you have to draw it to the bottom graph.
If this has helped you, please mark this answer as brainliest
You have to subtract the degrees like in this picture:
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
